A machine to convert gravity to mechanical energy # 2

[brian334]

Mondrasek,
The momentum of the falling 64 lb weight needs to be considered in any estimation of how much the tank will expand.
The momentum of the falling 64 lb. weight is the invention.

[mondrasek]

Brian,

Lets take a tube of any diameter that is longer than ten feet.  Cap one end.  Now start pushing the capped end straight down into a body of water.  It will resist this and push back up, right?  The further down you push, the more force it takes to push it down. How much force?  That is a function of the depth of the tube in the water and the diameter of the tube (and density of the water, ie. fresh or ocean).

The force that is pushing up on the submerged capped end is the surface area of the circular capped end times the pressure at that depth.  The pressure of the water at 10 feet deep is 4.454 psi greater than one atmosphere.  That means if the surface area of our tube end is exactly 1 square inch, it would be pushing our tube up with exactly 4.454 lbs of force.  If the tube was bigger in diameter and the end cap was exactly 2 square inches the force pushing up would be exactly 2 times that or 2 x 4.454 = 8.908 lbs of force.  So how many square inches of cap will push up with exactly 64 pounds of force?  64 / 4.454 = 14.3691 square inches.  And the size tube with a 14.3691 inch cross section is expressed by pi * r2 = 14.3691.  Solving for the radius r = 2.13865.  Two time the radius is the diameter = 4.2773.

So if you take a capped tube of diameter 4.2773 inches and make it weigh exactly 64 lbs it will sink upright in water of it's own weight to exactly 10 ft.  To make it go deeper you will need to add more weight or make it smaller in diameter.

Note in this example that the tube is open to the atmosphere at all times.  And with 10 feet of tube in the water it is not even displacing one cubic foot.  It needs to be 10.02 feet to displace 1 cubic foot.

M.

PS.  Had to try and post a few times because of web errors and noticed your new posts.  You said to ignore momentum for the hypothetical case.

[brian334]

Mondrasek,
Buoyancy is based on displacement not on depth. The amount of buoyancy a object has does not have anything to do with water pressure.

[brian334]

The general idea of the invention is that the momentum of the falling 64 lb. Weight would be enough to overcome the external water pressure.
Remember the weight falls about 11 inches inside the tank, also the moveable pulley gives the falling 64 lb. Weight a 2 to 1 mechanical advantage.

[brian334]

Notice in the drawing the weight moves about twice as far as the piston.