RESONANCE EFFECTS FOR EVERYONE TO SHARE

[armagdn03]

@Grumpy,

There should be a logical and sensible path by which we all *understand* why are things the way they are, and then applying that understanding we could create working circuits with little or no experimental effort. The experimentation has already been done for us in the past 200 years. The theory has already been laid out as well.

We need to start (re)learning (and unlearning of the dogma of later part of 20th century) and understanding what those giants of science in the past really meant and did...

Thats exactly what I have been trying to lead people into! If you want a working model check out my latest video, and start thinking about why input goes down, as output goes up.

Also, I seem to be running low on karma.....

@gotoluc
I believe if you want to find your max power output  for your signal generator you would want to match your load to your source impedance per the maximum power transfer therum, most sig gens are 50 ohms.

[najman100]

Hi everyone,

I just uploaded a new video and would like everyone who can check to see if my way of calculating the power is correct.

Please post your comments

Link to video: http://www.youtube.com/watch?v=-P8zch1De-Q

Thanks for your time.

Luc

Hello LUC
i just finished watching your vid it is interesting can you make a schematic drawing off all the set up ?

Thank You
Najman

[AbbaRue]

@gotoluc
I hope I'm wrong here but.
When you connected the 10 ohm load across the signal generator you got 0.256 Watts.
To do the comparison your coils would have to have a total resistance of 10 ohms as well.
Your signal generator will put out more wattage if connected to a lower resistance.
Just like your house wiring, the lower the resistance of the load the more power is drawn.
What wattage do you get across the signal generator output while it's connected to the coils?

Try replacing the 1 ohm resistor going to the board with the 10 ohm resistor
If you get more then 0.256 watts from the capacitor measurements then you must have more output then input.
Because you would have the 10 ohm resistor in series with the coils, the 10 ohm resistor would act as a current limiter.
And as such it would be impossible to have less then a 10 ohm load across your signal generator then.

The most important point to keep in mind here is lower resistance means higher current and thus higher wattage.
Higher resistance means lower current and thus lower wattage.

You replaced the 10 ohm resistor with the 3 coil setup which most likely has a much lower resistance then 10 ohms.
Even with the 1 ohm resistor in series.  But use a 10 ohm instead of the 1 ohm and then you will know for sure.

Another way to put it: If you connect three 10 ohm resistors in parallel you get 3.33 ohms.
1.6 x 1.6 = 2.56 / 3.33 = 0.776 Watts.  This is what your 3 coils circuit is drawing from the signal generator.
0.776 - 0.762 = 0.014          So your circuit is putting out 0.014 watts less then what you are putting in.

[duff]

Luc,

As you initially stated, the voltage across the 10 ohm resistor in parallel with your signal generator show 1.59Vrms.

P=V²/R = 1.59²/10 = 252.82 mW


If I understand how you have this wired, you have three 10 ohm resistors in
series with the 30,000uF cap??? Please provide a schematic so were clear on what
your doing.

So you have three series resistors: 3 x 10 = 30 ohms  across a voltage of 2.76V.
P = V²/R_Total
P = 2.76²/30 = 253mW

This is very close to unity if I understand how the components are connected. You should probably  measure the actual values of the components to get a better idea of where you are.


At the end of the video you show 200mV  across a 1 ohm resistor in
series with your input.

So your circuit is drawing:

I=E/R = 0.2/1 = 200mA

[gotoluc]

Hi AbbaRue and duff,

thanks for your replies and suggestions. I'm redoing my test 12 video and will have it up in a few hours.

What I'm trying to do is find a baseline way of testing my coils from now on and I was getting confused because of my lack of electronics measuring experience.

The new video will have a 10 Ohm resistor in series on the SG feed to the coils with the scope probes across it to measure the RMS so we can calculate the power in. Also, this time I will keep each coil output separate to its own 30,000uf cap with 10 Ohm load across it and each will have its own volt meter.

I hope this way will be easier to calculate total in and total out.

Thanks for you help

Luc