RESONANCE EFFECTS FOR EVERYONE TO SHARE

[gotoluc]

Hi everyone,

here is Groundloop's detailed diagram of my test setup with parts list and all.

Please understand that the mag wire, capacitors, diodes and resistors I used were all things I had on hand or salvaged from other things, so this is why (for example) the coils have two different wire gauges, the resistors are different and so one. I like to recycle as much as I can. I also have no job and no income, so I have to be creative

On this note!... I have to thank my friend Lucie who has a job and has let me stay at her home with supplied meal free of charge. Without her support I don't think I would be able to do as much as I have been doing.

Thank you once again Groundloop for your sleepless services to help all.

Luc

[Groundloop]

@najman100,

It is almost impossible to design an inverter that does not have any losses.
At best you get 80 - 90 % of the energy you put into the inverter back as
a usable output. The over unity in the circuit must be higher than  2 x the total
input usage to be able to loop back the output to the input. It is probably
simpler to design the coils to give you the voltage you need by designing
the secondary coils with enough turns, but when we starts to talk about
several Watts output then your idea will be a nice way to loop back energy.

@gotoluc,

I did the math on your 12VDC test.

Circuit input usage without any load = 0,60221 Watt.
Circuit input usage with coils connected = 1,54854 Watt.
Output on coil 1 with 10 ohm load resistor = 0,29584 Watt
Output on coil 2 with 5 ohm load resistor = 0,24642 Watt
Output total = 0,54226 Watt.

Circuit input usage - circuit switching loss = 1,54854 Watt - 0,60221 Watt = 0,94633 Watt.
So at 12VDC input voltage the circuit COP = 0,573. So at this low voltage the circuit runs at a little
over 50% efficiency. So I agree with you, high voltage switching in resonance is a must.

@TinselKoala,

Great video. You confirmed that the input usage did not go up when connecting the coil as a load.
Keep up the good work.

Groundloop.

[otto]

Hello all,

maybe a core?

Otto

[wattsup]

@groundloop

Great diagram as usual. Geez you guys are top level.

As with many threads that change situations as time progresses, can I just ask two questions as a re-cap.

1) Is the output of the circuit at f0/2 still dc reverse polarity pulsing. If yes, can anyone explain what this means relative to the input frequency from the frequency generator?

2) Regarding the output coming from the FG, does it require a minimum AC voltage capability?

OK last one.

3) If the circuit starts with the isolation transformer (IT), should the amps and voltage meters not be put on the input to the IT and not after the Variac, since the IT and the variac will also generate losses that should be part of the total equation including losses from the bridge rectifier?

OK last last one.

4) Based on question 3, is it not better to just use a battery as the input power (like @TK is doing). Then if you put a bridge on one of the two end outputs, you can maybe send it back to the battery and just see if there is any voltage drop on the battery.

Sorry for what may seem to be re-hash.

[Groundloop]

@wattsup,

1. f0 /2 means if the input frequency is f0 = 100 Hz then the output frequency is f0 / 2 = 50Hz.
The circuit triggers at each positive edge on the input pulse. So at the first positive edge the output
will will be positive on one end and negative (or ground) at the other. At the next positive edge input pulse
the output will be opposite. This will happen in sync with the input pulse. See attached drawing.

2. It is hard to understand what you are thinking on here but the switch makes pulsed DC on the output.
The switch takes the input DC voltage and connects to the output connector in an alternating way at
each input positive edge pulse. The minimum DC volt the switch can handle is 0 Volt. The maximum
voltage is set by the HEXFETs used and the IR2103. The IR2103 can handle up to 600 volt. So if you use
hexfet transistors that can take 600 volt then the absolute maximum input voltage the switch can take is 600 volt.
I will never recommend using that high voltage.

3 and 4. No not really. We want to measure how much power the coils is using. So in a ideal situation the measurement should be taken right at the switch output. If you use a 50 volt battery as input then there is no losses in transformers etc. Since we know how much the switch itself uses (as heat) then we can easily calculate how much power the coil is getting from the switch. The resistors (1%) has a known value so it is easy to calculate how much power we get out of the coils into the load. So sometime in the future we can use 4 x 12 volt batteries as a input to get 48 volt DC. Then the output coil(s) will be designed to give out more than 48 volt. Then you can loop back the output to the input at minimal losses. But the challenge will be designing coils that can deliver more output without loading the input source. The challenge with many coils is to get ALL of them to resonate at the same frequency.

I hope this answered some of your questions.

Groundloop.