Sjack Abeling Gravity Wheel and the Worlds first Weight Power Plant

[hansvonlieven]

It is YOUR perpetual motion machine Omnibus if you really look at it. The fetters look different but they act just the same. LOL

Hans von Lieven

[Omnibus]

It is YOUR perpetual motion machine Omnibus if you really look at it. The fetters look different but they act just the same. LOL

Hans von Lieven

No, it isn't. I explained on several occasions that the perpetuum mobile doesn't have specifically that particular obstruction. Wonder what is that desire in you to  reincarnate questions that have already been resolved?

[stgpcm]

No, guide is sideways. Besides, the rightward or leftward vector isn't under consideration when we talk about torque. Torque is only the product of the normal component (pointing downwards) and the length of the arm.

I sorry, I was unclear. The guide is diagonal, but far closer to vertical - so left/right is far more appropriate then the above/below I used.

When I said is the weight above the guide, I meant is the center of mass of the weight above the point of interaction between the physical weight and the physical guide (if it is, it is to the right of the guide)

when I was talking about the leftward vector, I was refering to the left cyan arrow; which, if the weight is to the right of the guide, this vector is acting on the guide as well as the wheel. Far more interesting though, is the right component. This points into space. It accelerating the mass towards the hub, as there is nothing to stop it - your weight has fallen off your wheel, and is not following the path your guide suggests.

If, on the other hand the weight is to the left (and below) the guide why did you resolve against it? at that point the the force due to gravity on the weight isn't acting against the guide (given that you are using reactive methods for calculating the torque)

[Omnibus]

No, as I said, the normal vector is acting on the arm solely, causing the torque. The normal vector is a result of the decomposition of other earlier vectors where the action on the guide has already been taken into account. That normal vector, acting solely to cause torque is an outcome from such previous decomposition of vectors.

[Omnibus]

These are the net torque data for the tracks shown. As seen one attractive possibility is the ellipsoid track which is not only the most convenient to analyze but is also the easiest to manufacture. Of course, the obvious advantage some of track forms provide will be mitigated by the hindrances due to the friction forces which will present themselves such that the order of preferable tracks would become different from what is apparent from the figure below. Now, it’s interesting to find a method for the quantitative assessment of these opposing friction forces to have this analysis be of greater help in the manufacturing of the device.