STEORN DEMO LIVE & STREAM in Dublin, December 15th, 10 AM

[LarryC]

@Omnibus,

There are three Power formulas: P=EI  P=E^2/R  P=I^2R

The second two were derived using Ohm's law equivalent as follows:
P = E I = E (E / R) = E^2/ R

P = E I = (I R) I    = I^2 R

So I changed the formula from EI, which is bias by signs, to E^2/R in the 700Hz data.

Omni world results    Pin = 2.26E-06 Pout = 9.48E-06

Real world results     Pin = 1.84E-04 Pout = 9.48E-06

Oops, Omni OU is lost big time again.

Please teach us the physics and reason against the use of E^2/R.

Regards, Larry

[broli]

@Omnibus,

There are three Power formulas: P=EI  P=E^2/R  P=I^2R

The second two were derived using Ohm's law equivalent as follows:
P = E I = E (E / R) = E^2/ R

P = E I = (I R) I    = I^2 R

So I changed the formula from EI, which is bias by signs, to E^2/R in the 700Hz data.

Omni world results    Pin = 2.26E-06 Pout = 9.48E-06

Real world results     Pin = 1.84E-04 Pout = 9.48E-06

Oops, Omni OU is lost big time again.

Please teach us the physics and reason against the use of E^2/R.

Regards, Larry

[Omnibus]

@Omnibus,

There are three Power formulas: P=EI  P=E^2/R  P=I^2R

The second two were derived using Ohm's law equivalent as follows:
P = E I = E (E / R) = E^2/ R

P = E I = (I R) I    = I^2 R

So I changed the formula from EI, which is bias by signs, to E^2/R in the 700Hz data.

Omni world results    Pin = 2.26E-06 Pout = 9.48E-06

Real world results     Pin = 1.84E-04 Pout = 9.48E-06

Oops, Omni OU is lost big time again.

Please teach us the physics and reason against the use of E^2/R.

Regards, Larry

@LarryC,

Cut this gibberish at once. Follow the rules of science and don't try to finagle out of the situation you've placed yourself in. Anyone can make mistakes but to be stubborn and not willing to learn as you're doing is not the way to go in a discussion like this. Such stubbornness only clogs the discussion.

[Omnibus]

@All,

Of course P = E^2/R should not be used in this case because it isn't only Ohm's law that holds in this situation. To calculate power in this case you must use the real measured value of the current I as well which does not correspond here to the voltage V through Ohm's law.

[broli]

@All,

Of course P = E^2/R should not be used in this case because it isn't only Ohm's law that holds in this situation.

Not to mention E is not over R but over R and L, so of course it can't be used to calculate power through resistance  . But at this point he's at the level of a troll so no need for an educated correction.