Hi guys,
I have achieved unipolar electricity. As you know, we need a positive and a negative pole if we want to run any device. But I have achieved it using only 2 positives or 2 negatives poles.
This is possible if we know to make a right battery configurations as EV Gray Said.
Hmmn.
Sure looks like more than one wire to me.
But meanwhile, with a slightly more complex apparatus, I really can use just one wire--you might like to look at my recent "resonance" videos on YT and in the "resonance effects for everyone" thread here.
(Oh, I see what you mean, you've got your batteries hooked up all funny. Cool. Does that mean you only need to use one pole of the battery? That's not what I see in the pictures, it still looks like both poles are hooked up. )
Quote from: TinselKoala on December 30, 2008, 03:34:18 PM
Hmmn.
Sure looks like more than one wire to me.
But meanwhile, with a slightly more complex apparatus, I really can use just one wire--you might like to look at my recent "resonance" videos on YT and in the "resonance effects for everyone" thread here.
(Oh, I see what you mean, you've got your batteries hooked up all funny. Cool. Does that mean you only need to use one pole of the battery? That's not what I see in the pictures, it still looks like both poles are hooked up. )
Using only 1 wire it doesn't works. But... What really is happening here? Using 2 positive or 2 negatives poles... we can run any device.
This is cold/radiant/negative electricity?
so your circuit is:
(One side of light bulb) ---> +(bat1)- ----> +(bat2)- -----> -(bat3)+ ----> (back to other side of bulb).
So, technically (and misleadingly) both sides of the bulb are hooked to a positive battery pole, and you are claiming that these two wires could be replaced with one.
Am I correct so far?
Let's assume I am, so I'll just keep going.
Now, if you hook a voltmeter across the bulb, you will indeed find that one side of the bulb is "more positive" than the other; that is, there will be a voltage across the bulb, with one side positive and one side negative.
Try it and see.
On the other hand, your hypothesis says you can replace the two wires with a single wire and still light the bulb.
Try it and see.
yes, the battery configuration is
+(batery)-+(batery)--(batery)+
I have just replaced 2 wires with 1 and it doesn't work... but...
Why the device can still work using 2 positives or 2 negatives poles??
I have tried this experiment because EV Gray used a technique called "Positive Splitting" and I found a schematic showing the experiment I have just made.
I'm just splitting the positive as you can see in the picture.
Anyone have a 'possible' answer to this phenomenon?
Why the device can work with 2 negative or positives poles?
Quote from: Magnethos on December 30, 2008, 04:28:47 PM
yes, the battery configuration is
+(batery)-+(batery)--(batery)+
I have just replaced 2 wires with 1 and it doesn't work... but...
Why the device can still work using 2 positives or 2 negatives poles??
I have tried this experiment because EV Gray used a technique called "Positive Splitting" and I found a schematic showing the experiment I have just made.
I've tried this, and the one battery acts like a diode rather than a battery, this doesn't seem to make any sense either...that is, with a one wire circuit.
Your pictures are a little fuzzy, perhaps a repost of an overhead shot.
Quote from: jadaro2600 on December 30, 2008, 11:51:03 PM
I've tried this, and the one battery acts like a diode rather than a battery, this doesn't seem to make any sense either...that is, with a one wire circuit.
Your pictures are a little fuzzy, perhaps a repost of an overhead shot.
One wire doesn't works for me if I want to run a motor.
the key is the battery configuration, because I think this is Cold Electricity. Yes, in cold electricity a capacitor has inductance, so the electrical properties in cold electricity are different. So, if your battery acts like a diode... I'm almost 100% sure that this kind of electricity is Cold Electricity.
We can use both 2 positive or 2 negative poles to run any device in cold electricity. Maybe this is the easiest way to produce radiant/cold electricity.
You will need also more voltage and less current, because cold electricity is the opposite of hot electricity. Hot works in low volt-high amps. Cold works in low amps-high volt.
This is why my the brightness of my light bulb is low when I use cold electrical current.
So... guys, I'm going to build a "possible" Hot to Cold Electricity Transformer.
The idea is transform any Battery (hot electricity) to a Cold Electricity source.
Why not try to run the cold juice through a JT or a flash camera circuit?
Quote from: Doug1 on December 31, 2008, 08:09:35 AM
Why not try to run the cold juice through a JT or a flash camera circuit?
Why? Explain me more, please.
Quote from: Magnethos on December 30, 2008, 05:49:31 PM
I'm just splitting the positive as you can see in the picture.
Anyone have a 'possible' answer to this phenomenon?
Why the device can work with 2 negative or positives poles?
The series connection of the two top batteries is charging the lower battery. The voltage should be dropping on the two top batteries and rising on the lower battery.
Best that you put two batteries in parallel down at the bottom. This way when they are all charged up you flip them into a series connection and the top ones into a parallel and transfer the voltage back the other way for some more light.
Quote from: Magnethos on December 31, 2008, 08:31:45 AM
Why? Explain me more, please.
Just out of curiosity I guess. I would do it myself but I am working on another item.
Quote from: Doug1 on December 31, 2008, 10:05:44 AM
Just out of curiosity I guess. I would do it myself but I am working on another item.
If you post here some schematics, I will try it.
I still don't know if this is cold electricity or only a simple effect of hot electricity. ???
I'm going to get crazy.... ???
Now the same effect is possible using only 2 batteries in series
Motor +(battery1)--(battery2)+ Motor
The motor runs more slow than when I connect only 1 battery (motor +bat- motor)
So... the power drops when I use motor +bat- -bat+ motor
Some explanation please.... because each time I understand less and less... ???
EV Gray in the News:
When Gray said "split the positive", the faces of two knowledgeable physicists screwed up in bewilderment. Normally, electricity consists of positive and negative particles. But Gray's system is capable of using one or the other separately and effectively
I already explained this circuit before.
The circuit has 2 batteries connected in parallel with one battery.
The 2 batteries in series are charging up the single battery through the lightbulb.
This is identical to the Young effect were one capacitor charges up the other through a motor.
Only this circuit is using batteries and a light bulb instead.
Quote from: AbbaRue on December 31, 2008, 10:46:21 AM
I already explained this circuit before.
The circuit has 2 batteries connected in parallel with one battery.
The 2 batteries in series are charging up the single battery through the lightbulb.
This is identical to the Young effect were one capacitor charges up the other through a motor.
Only this circuit is using a lightbulb instead.
Of course, now I understand this. Thanks.
If you had a battery charger you could use it in place of the 2 batteries in series.
You would connect the negative terminal of the charger to the negative of the battery.
And then you would connect the positive of the charger to one side of the light bulb.
And connect the positive of the battery up to the other side of the light bulb.
Then you could light the bulb at the same time as you charge your battery.
Is this a joke?
When the light goes out all batteries/capacitors should be at same voltage. Then switch em from series to parallel. Do it again. :)
Quote from: sparks on December 31, 2008, 05:59:56 PM
When the light goes out all batteries/capacitors should be at same voltage. Then switch em from series to parallel. Do it again. :)
Sorry I made a mistake. When current stops flowing at useful levels then the batteries will be for example; Topbattery1 6volts topbattery two 6volts bottom batteries at 11.5. So we take the two 11.5 and series connect for 23volts and dump through light bulb into parallel batteries starting at 6volts. The system will now charge the bottom batteries up until we have the following: top batteries back to 6volts each and bottom batteries at 11.5. Now the cycle goes on and on.
@Loner
Yes it's a Tesla switch scheme. Of course the inability of the capacitors to respond efficiently to the input voltage will have the system ring down. Definitely not cold electricity. Cold electricity is generated by the polarization of the field itself and little to do with mass. Just wanted to show an efficient way of using voltage so I'm outta here with any more Tesla Switching Schemes. :D
Quote from: sparks on January 01, 2009, 11:58:17 AM
Sorry I made a mistake. When current stops flowing at useful levels then the batteries will be for example; Topbattery1 6volts topbattery two 6volts bottom batteries at 11.5. So we take the two 11.5 and series connect for 23volts and dump through light bulb into parallel batteries starting at 6volts. The system will now charge the bottom batteries up until we have the following: top batteries back to 6volts each and bottom batteries at 11.5. Now the cycle goes on and on.
I can't run the motor or light the light bulb using the 3 batteries system (using 2 positives), but I can light the light bulb or run the motor if I use the common Negative & Positive connection. I have to say that batteries are of low quality.
Uhmmm... very very insteresting your idea. I use 1.5 Volt non-rechargeable batteries. I think I can replicate what you say using my 1.5V batteries. Right?
I have understood the voltage process, but... what about the current?
Your all kidding me right? for electricity to work you don't need a Positive and a Negative current. You need a higher and a lower potential. In other words electricity is a FLOW it tries to balance the charge by flowing from something that has more charge to something that has less charge. If you have 2 "Positive" terminals one that has either more current available to it or one that has more charge available to it then the other the electricity will flow to try and balance out the connected charges. You want something the ponder on rather than trying to "Force" charge into a battery (thats what your doing on your lower potential side BTW, and that can blow up that battery if your not careful) is if you have power source "A" which is 9v+ and has a potential current of 2amp connected to "B" a 12v+ 1.5amp which way will the charge flow? both are the same Watts but have different atributes.
Unipolar electricity, Cold electricity...? I'd just like to know, when will Magnethos stop spamming this board with countless threads about his electricity misconceptions and delusions?
Quote from: Magnethos on December 31, 2008, 05:25:11 AM
One wire doesn't works for me if I want to run a motor.
the key is the battery configuration, because I think this is Cold Electricity. Yes, in cold electricity a capacitor has inductance, so the electrical properties in cold electricity are different. So, if your battery acts like a diode... I'm almost 100% sure that this kind of electricity is Cold Electricity.
We can use both 2 positive or 2 negative poles to run any device in cold electricity. Maybe this is the easiest way to produce radiant/cold electricity.
You will need also more voltage and less current, because cold electricity is the opposite of hot electricity. Hot works in low volt-high amps. Cold works in low amps-high volt.
This is why my the brightness of my light bulb is low when I use cold electrical current.
This is all wrong.... You do indeed have two like poles. but what you have is 1 pole with 3v, and 1 pole with 1.5v together they make a 1.5v circuit, and would be the same as connecting ONE battery straight to the lightbulb,, but cooincidently will last Three times as long. The battery is not acting as a diode, but rather as a 1-way resistor. because it has twice the current potential in one direction, vs. in the other.
the electrical properties are 'different' because you're dealing with the other side of a circuit and trying to compare those results to a circuit with a '0 ground'.
your ground is positive, 1.5v. once you account for this things wil start making a lot more sense.
Your configuration of batteries has this effect:
1.5v + 1.5v = 3v (These are the two in normal series, they become, effectively, a single 3v battery)
This 3v is then added to a 1.5v battery in opposition (hooked up backwards)
so....
3v - 1.5v = 1.5v
You have 1.5v powering that light bulb in the configuration described above. The "larger" battery wins, but is reduced by the voltage of the opposing battery.
Quote from: CrazyEwok on January 01, 2009, 08:53:53 PM
Your all kidding me right? for electricity to work you don't need a Positive and a Negative current. You need a higher and a lower potential. In other words electricity is a FLOW it tries to balance the charge by flowing from something that has more charge to something that has less charge. If you have 2 "Positive" terminals one that has either more current available to it or one that has more charge available to it then the other the electricity will flow to try and balance out the connected charges. You want something the ponder on rather than trying to "Force" charge into a battery (thats what your doing on your lower potential side BTW, and that can blow up that battery if your not careful) is if you have power source "A" which is 9v+ and has a potential current of 2amp connected to "B" a 12v+ 1.5amp which way will the charge flow? both are the same Watts but have different atributes.
Very usefull comment, thanks
Quote from: spinner on January 01, 2009, 10:27:53 PM
Unipolar electricity, Cold electricity...? I'd just like to know, when will Magnethos stop spamming this board with countless threads about his electricity misconceptions and delusions?
I'm just asking, this section is called HALF-BAKED ideas. So I can ask it.
If you have a brilliant idea, post it here, because I will learn from it and I will stop "spamming" this board. Meanwhile I will ask all my doubts here. ;)
Quote from: TCadd on January 01, 2009, 11:45:36 PM
Your configuration of batteries has this effect:
1.5v + 1.5v = 3v (These are the two in normal series, they become, effectively, a single 3v battery)
This 3v is then added to a 1.5v battery in opposition (hooked up backwards)
so....
3v - 1.5v = 1.5v
You have 1.5v powering that light bulb in the configuration described above. The "larger" battery wins, but is reduced by the voltage of the opposing battery.
Yes, that is the info I was looking for.
A battery can be looked at as a negative resistor.
I think that is the idea of this circuit arrangement.
But the warning given is important, the single battery could explode if using regular batteries.
We should make sure we use some type of rechargeable battery.
Does anyone know how a rechargeable alkali battery would work in such a circuit?
Would this type of circuit damage them?
They need a special recharger and they put out over 1.5 volts.
Most rechargeables put out 1.2 to 1.25 Volts.
Here's some one-wire lights.
But unipolar? I don't think so.
http://www.youtube.com/watch?v=MBUfaYi02WI
Quote from: Magnethos on January 02, 2009, 04:45:33 AM
I'm just asking, this section is called HALF-BAKED ideas. So I can ask it.
If you have a brilliant idea, post it here, because I will learn from it and I will stop "spamming" this board. Meanwhile I will ask all my doubts here. ;)
Magnethos, I'm sorry for my little critique, or my "unpleasant" post...
I think you're a good guy! I only had objections with your continuation of asking
the same questions in MANY(!) threads of yours over the last months....
Topics which basically deals with Voltage, Current, Power,... (in electrotechnical terms) are really quite well understood (for quite some time now)...
Dealing with batteries,.. "voltage",.. "el. currents", etc... is
really just a common electrotechnical knowledge...
The "case" you are presenting in this thread is a simple one, and the answer was given to you by many members, many times..
Based on the cumulative knowledge of physics/electrotechnics, it all cames down to the simple equations of e.g. "Ohm's, Kirchhoff's Law's"... Or adding/substracting the "Voltage differences" from all the batteries(sources) and consumers included in the el. circuit...
There is no "unipolar electricity", there is no "Cold electricity", electrical circuits are not
really a "single wire" ones,... etc...etc...
If you choose to believe the "fringe science" more than the current knowledge, than that's your personal choice....
Anybody claiming the opposite should present the solid proof. In case you really have something new, in days/weeks (maybee months), the majority of "orthodox science" would admit the (centuries long) mistake... No doubt about that!
All the energy conversions are happening just because there's a "POTENTIAL Difference" (Voltage).... First, there must be an ability to "perform"...
And secondly, a trigger mechanism to sparkle the "conversion".... (which is equal to establishing a "closed" el. circuit)...
Then, a current flows...
In the future, if you have some questions, please,check the www info (or even this board) for the answers first...
Why don't you use WikiPedia? It's definitely a very knowledgeable source...?
And, a "half-baked ideas" topics is not meant to deal with a basic misunderstandings and misconceptions....
It is suppose to bring us a good, possible, "could be" working ideas & methods to achieve something more....
Cheers!
Quote from: spinner on January 03, 2009, 04:13:28 AM
Magnethos, I'm sorry for my little critique, or my "unpleasant" post...
I think you're a good guy! I only had objections with your continuation of asking the same questions in MANY(!) threads of yours over the last months....
Topics which basically deals with Voltage, Current, Power,... (in electrotechnical terms) are really quite well understood (for quite some time now)...
Dealing with batteries,.. "voltage",.. "el. currents", etc... is really just a common electrotechnical knowledge...
The "case" you are presenting in this thread is a simple one, and the answer was given to you by many members, many times..
Based on the cumulative knowledge of physics/electrotechnics, it all cames down to the simple equations of e.g. "Ohm's, Kirchhoff's Law's"... Or adding/substracting the "Voltage differences" from all the batteries(sources) and consumers included in the el. circuit...
There is no "unipolar electricity", there is no "Cold electricity", electrical circuits are not really a "single wire" ones,... etc...etc...
If you choose to believe the "fringe science" more than the current knowledge, than that's your personal choice....
Anybody claiming the opposite should present the solid proof. In case you really have something new, in days/weeks (maybee months), the majority of "orthodox science" would admit the (centuries long) mistake... No doubt about that!
All the energy conversions are happening just because there's a "POTENTIAL Difference" (Voltage).... First, there must be an ability to "perform"...
And secondly, a trigger mechanism to sparkle the "conversion".... (which is equal to establishing a "closed" el. circuit)...
Then, a current flows...
In the future, if you have some questions, please,check the www info (or even this board) for the answers first...
Why don't you use WikiPedia? It's definitely a very knowledgeable source...?
And, a "half-baked ideas" topics is not meant to deal with a basic misunderstandings and misconceptions....
It is suppose to bring us a good, possible, "could be" working ideas & methods to achieve something more....
Cheers!
Man, I'm 100% agree with you!
The problem is I have a mixed knowledge, a bit from orthodox science and a bit from the fringe science.
I know a bit about everything, but I don't have a deep knowledge about any field. So, that is the reason I'm always asking the same and people are always replying me the same. People believes in orthodox science and I'm not agree with common science and I talk about unproven science.
Maybe the best choice now would be a physic forum instead of free enegy forum. I need to learn more about orthodox physics, and start experimenting little by little.
For now, cold electricity doesn't exists. I have seem some projects, but anyone haven't sucessfull replicated and used cold electrical current. If I'm very interested, the best thing is start learning common science, then learn fringe science and experiment with both common and fringe science, and, If I found something interesting. Post Results instead asking Unknow things. Maybe in some moment I could find a interesting thing and I could share the knowledge instead of trying that others help me.
Of course, I have to study hard, and work hard. There is no other choice. If my efforts are correct and enough, the results should come to me automatically.
Good comment man!
I wouldn't give up on that cold electricty. When we put voltage to a diode there is inside the crystals a migration of "holes" in the diode towards the negative charged plate. Same thing in a piece of wire. The hole in the valence shell of the copper molecules migrates toward the cathode. Now this migration of positive charged space is without the constraints of mass like inertia and speed of light it is migration of charge not migration of charge carriers. So there has to be a time in a diode where the holes are migrating towards the cathode a hell of alot faster than the electrons are moving towards the anode. Of course when the electrons start to migrate they create heat because of collisions with other atoms and photon radiation due to these collisions occurs. Hot electricity. But in that very first instant of voltage application the migration and concentration of the holes before the electron mass responds gives a window of massless migration of charge or polarization of the dielectric field without the constraints of mass velocity gain. Splitting the postive I'm not sure. Maybe clumping the positive? :)
Quote from: sparks on January 03, 2009, 12:09:13 PM
...this migration of positive charged space is without the constraints of mass like inertia and speed of light it is migration of charge not migration of charge carriers. So there has to be a time in a diode where the holes are migrating towards the cathode a hell of alot faster than the electrons are moving towards the anode...
...and if we brake the connection before the electrons start their migration?
Quote from: sparks on January 03, 2009, 12:09:13 PM
I wouldn't give up on that cold electricty. When we put voltage to a diode there is inside the crystals a migration of "holes" in the diode towards the negative charged plate. Same thing in a piece of wire. The hole in the valence shell of the copper molecules migrates toward the cathode. Now this migration of positive charged space is without the constraints of mass like inertia and speed of light it is migration of charge not migration of charge carriers. So there has to be a time in a diode where the holes are migrating towards the cathode a hell of alot faster than the electrons are moving towards the anode. Of course when the electrons start to migrate they create heat because of collisions with other atoms and photon radiation due to these collisions occurs. Hot electricity. But in that very first instant of voltage application the migration and concentration of the holes before the electron mass responds gives a window of massless migration of charge or polarization of the dielectric field without the constraints of mass velocity gain. Splitting the postive I'm not sure. Maybe clumping the positive? :)
HV impulses make coax "jump" like "jumper cables" for an automobile.
Not splitting the positive - just keeping it positive
Quote from: Rosphere on January 03, 2009, 01:18:25 PM
...and if we brake the connection before the electrons start their migration?
Then we begin to work with the "bold" part of Spark's message above - which is the cold current.
@rosphere
Honestly I have no frigging clue! But I do suspect that having a concentration of voided space (vacuum) does not go unnoticed by the field surrounding the diode.
@Grumpy
Maybe why the coax jumps is it is sitting in an electric pressure field. I include a video showing some pressure anomalies. Reminds me of Buzz's cavitation theory. http://www.youtube.com/watch?v=YKivPSVGpsw&feature=related
Quote from: sparks on January 04, 2009, 12:10:54 PM
@Grumpy
Maybe why the coax jumps is it is sitting in an electric pressure field. I include a video showing some pressure anomalies. Reminds me of Buzz's cavitation theory. http://www.youtube.com/watch?v=YKivPSVGpsw&feature=related
aren't you a smart one, sparks..
Quote from: sparks on January 03, 2009, 07:17:54 PM
@rosphere
Honestly I have no frigging clue! But I do suspect that having a concentration of voided space (vacuum) does not go unnoticed by the field surrounding the diode.
Your explanations are exact.