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Overunity Machines Forum



Electrical igniter for gas engines A keystone to understanding by Magluvin

Started by Magluvin, March 01, 2010, 01:30:50 AM

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0 Members and 3 Guests are viewing this topic.

woopy

at king Magluvin

thank's a lot for the soft and code

it work really well

But the best for today it works also IN REAL LIFE

i took your  circuit with the sim and put 30 volt at the battery  with 2 cap of 47 microF 2 BAT 43 diode and the secondary of the MOT with a resistance of 107 OHMs and 19 H inductance, and the sim results was very encouraging

Than i did it in real with the real things

And i played with this since 2 hours now. And as Forest say it is very dependant from the switching. But the source voltage goes down about from 30 volts to 21.8 that is a lost of  8.2 volts and the receiver get 15.7 volts (from 0 volts ) for example. I see in this test example a gain of nearly 200 %. Not bad at all for a first test. ;D

BRAVO MAN

let's go on the good way

i think i have an explanation regarding the 1/2* C*V^2 formula which is not adapted at what we are doing. But I have to go now . Will contact later

BUT BRAVO BRAVO BRAVO

good luck at all

Laurent

Magluvin

This is what Nulpoints posted at Roses thread....

hi Magzzzz

it would be great to think 'contrariwise', but sadly the only thing here that is Overunity is your enthusiasm!!  ;)

at the start, the input 10uF cap charged to 1000V holds 5000mJoules

at the end, the input 10uF cap at 990V holds 4901mJoules

so the input 10uF cap has supplied 99 mJoules to the 'Believe' circuit

the output 10uF cap at 132V holds 87mJoules
(ignoring the 0.5mJoule of 10V on 10uF)


Efficiency = 87/99 = 88%


if you want to even approach 100% then you need to transfer the charge from input to output in many steps of smaller energy transfer

it took me a year, using the same circuit arrangement in 2008, to confirm that the only things which are incorrect in the EE text books are that the value of charge-separation in an isolated circuit like this is NOT constant - and the energy dissipated : energy stored ratio is not always 1 : 1 as claimed

i've already given you & woopy a link to the thread which contains my results so i won't include it again here

i'm not trying to be negative about your work - i admire your zeal - i would like to save you guys from wasting your valuable time

regards
np


Im seeing the picture here now. But we still have a chance here.

We have to have more mjoules out than was taken from the source cap.

Forests figures seem to work here.   This is Forests post.....


Mags

From your circuit I can get above 730V in output cap while source cap level down to 600V. Always above 1kV when taking sum.
Evidently there is gain and gain depends on the time when we cutoff connection to source cap - meaning flywheel effect depends on resonance between inductor and output cap and the period of charging them from source.
Resonant energy systems.

I have one idea to test.



Here we have more voltage on the output vs what was taken from the source cap. Is that what we might be looking for to get a gain when we calculate?  It just may do the trick. Im at lunch so no time to check.

If we calculate what we took on the source, being calculate total to start minus what is left, in joules, then calculate the amount in the reciever cap, did we make it over the top here?

I have not gone through all the cutoff points yet.

Woops or forest, if you can work on those numbers that forest had presented, and see if we are good.  I will do it also this evening. We need to nail this down.  =]

Thanks guys for all your input here.  ;]   it has been great.  ;]  We have some turned over some stones and have made it past a couple road blocks here so far. We cant really expect not to have problems all the way. Some may quit now, and never find the gold ring in the sand.
Be back later.  =]


Mags

Montec

Hello all
Maximum energy transference between a source and a load happens when the impedance of the source equals the impedance of the load. This means that one half the energy is left in the source as heat, etc. Is this where the 1/2 figure comes into play in the EE text books?

:)
 

forest

Ok,I've got what I wanted to check. Simulation don't say you truth but it can show remnant of it.
Charge source cap then quickly discharge in impulses into output cap in the circuit like that in picture , once you get it right output cap will be charged steadily above 800V and yet there is very high freqency oscillation. I've got up to 4V on inductor in disconnected circuit ! Steady.
Might be and error in simulation but I doubt. Looks like displacement current oscillating aka electrostatic like.

forest

Look at the time at the picture.Firs scope shot on left is inductor ,then resistor then capacitor (output one)