I have to take a step outside of conventional electricity when it comes to static induction machines


Science tries their best to relate the two technologies.
They even go so far as to mimick the other, with step-up transformers
And capacitor cascades


But it is still not the same. We still cannot tame the static, anymore than we can bring our
Electricity to life.


Period.


The old form of energy directly affects physical matter.
It comes explicitly in two phases.
I know these to be electrons, and positrons.


Our electricity only uses one half.


It's about that simple.


We don't have the technology to prove it, or I should I say our technology is not capable.
Because it only uses half.


But I can prove it atomically, and I can prove it by the effects it has on physical matter.
Our form of electricity cannot.


We can make a positron now, with our particle accelerators and high powered lasers
Mathematically they are the same thing that is in our "positive" Leyden jar.


Vitreous
And
Resinous


Electrons
And
Positrons


The two together are E=mc^2
Electron = 1/2mc^2 or 1.602 x 10^-19 J


I'm not sure if opening one end of two capacitors (+/-) would be the same thing....
One to ground, one to +
But you would have to run a secondary identical circuit off the two open leads.
And allow the induced voltages to oscillate 180-degrees out of phase.

I have tamed the static.

Some of it anyway.   

http://www.youtube.com/watch?v=f-aP7sk48jw

You are right if you are talking about a closed circuit. The total energy should be from the source if the environment factor remains normal.

Quote from: sm0ky2 on December 18, 2017, 07:51:24 AM
"Subject To losses"?
That's your explanation?


Power is power. V*I


Whatever is lost after that is subtracted from the total.
It doesn't change the total energy involved.


At what size does a static-electric generator
Equal to the power of a conventional steam-electric generator?


And how much "energy" has to be put into each to achieve this power?


"Static" is only static until you allow it to move.
In the same manner that the potential energy of a battery is "static".
The same can be said of any capacitor.


The condenser can dump 100% of its energy at one time.
The 'actual current' is a large spike. The 'average current over time'
Is the value commonly used, this is why it is often micro amps in quantity.
Instantaneous current is all induction cares about.
This is an important distinction when dealing with high frequencies.


You can melt steel with a 'static' discharge.
To do this with a conventional generator connected to an arc welder
Requires exponentially greater quantities of energy.


The math is available for both of these situations.


If we take an absolute value for the energy required, it becomes apparent that
Our conventional generator and arc welder are less than 1% efficient.

I am not sure what you are talking about.
From what i can see there is no secret here if your circuit is a simple closed circuit. No secret means that there is no OU.  [size=78%]There is nothing abnormal unless R<=0.[/size]
[size=78%]
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Quote from: Tajerek on December 18, 2017, 04:29:22 PM


Formula 2) The Charge on capacitor Q = C* V_source*[1-Exponential(-t/RC)]

This is again great secret for those who can see. Notice how the charge (ie. the energy) overtime is defined in relation only the voltage of the source , R , and C . No mention of current here because it doesn't affect the charge on the cap. Only voltage does. You don't believe it ? look again at the formula. The overunity secret is right there.

The overunity secret is magnetic field