Quote from: Delburt Phend on May 08, 2018, 08:13:44 PM
https://www.youtube.com/watch?v=oeG7RcSodn8

The mass difference, of cylinder to sphere, is only about 3 to 1.There are not two spheres only one. Half the motion is on the other side of the center of mass still in the mass of the cylinder. The motion is complex.

All the motion comes from gravitational potential energy. The sphere's tether gets very long, but the sphere is moving very fast.

If angular momentum is conserved the arc velocity of the sphere would become only .375 of the original speed of the rotating cylinder; because of the long radius. It is obvious that the sphere velocity is much higher. And the gravitationally source is not at the center of rotation: as is the situation in space.

For kinetic energy to be conserved the top velocity of the sphere would have an increase from only 1 to 1.73.

If momentum were to be conserved the velocity of the sphere would have an increase from 1 to 3. These higher speeds seem more apparent; especially since the sphere can stop and lift a falling cylinder.

One might ask why the sphere does not return the cylinder to the top starting position. Well the cylinder's spinning first has to be stopped and that takes time. It takes time for the sphere to restart the spin of the cylinder in the opposite direction. And it would take time to bring the cylinder back up to another stopped position at the top. Going from stop to stop would take a ton of time. And in all of this time the cylinder is under gravitational acceleration.  It is amazing that the single sphere gets the cylinder as far back up as it does.

Sorry: that the release position is not in view; it starts just above the viewing area. There are two strings on the cylinder and the sphere is in the center.

I think these kinetic, gravitic, whatevertic ideas are a good thought experiment, but when you have your "analogy" figured out with the balls and strings then you want to convert that idea to something that is not diminished by air drag or friction. Humans think you want to go bigger and bigger, but the correct answer might be to go smaller and smaller. maybe even to molecular levels. If you got problems in transfering the energy back from molecular level then just heat water with it and use a turbine.

Even electricity has inertia so if your idea is kinetic, you might be able to do a solid state version of it.

https://www.youtube.com/watch?v=8Q7L2BOYkjE

The reason this works is because you can apply the same quantity of force for different periods of time. You can apply the force for a short period of time on the side going up; and on the side going down you can apply the same force for a long period of time. This process will produce massive quantities of energy.

By throwing a mass up fast; you can pass units of distance that result in only minimal loss of momentum.  By changing the arrangement of the applied force (from the same mass); these passed units of distance can give you larger units of momentum on the way back down.  Momentum is a function of time.

An example for a one kilogram mass: The first meter of an upward throw of 100 meters only costs you .222 units of momentum. The same meter of drop on the way back down can give you 4.429 units of momentum. The speed of the upward throw of 100 meters; changes from only (square root of (100 m*2*9.81m/sec/sec) 44.294 m/sec to 44.0724 m/sec in the first meter up. But you get 4.429 units of momentum on each individual meter on the way back down.  You gain (4.429 -.222) 4.207 units of momentum.

It takes .4515 sec to drop one meter: that means you have applied the force for .4515 second.

If you are moving up at 100 meter per second you can cross 19 meters in .4515 second.

On the way back down 'each' of these 19 units of distance can be crossed in .4515 seconds; this is 18 more units of time from the same distance of 19 meters. Gravity does not make you pay for these 18 extra units of 'time' over which the force is applied.
 
In the kilowatt hour you are paying for each unit of time 'of the applied force'; you won't get 18 free units.  Gravity will apply the force for free.

Quote from: Delburt Phend on May 19, 2018, 11:51:52 AM
https://www.youtube.com/watch?v=8Q7L2BOYkjE

What were the parameters of this experiment, the mass of the tube and ball? How come did the the tube start rotating when you let it go, was it weighted on one side? Did you calculate the amount of energy that was transferred between the two?

Do not repeat this experiment.
Even after the sphere careens off of a well-padded floor; it then snaps a knot of a 65 pound test fluorocarbon fishing line; and then bounces off of a cardboard box and crosses back (above the viewing area) to the other side the room and hits the chair I had been sitting in.  This one might be unsafe; and all of the experiments have some danger.   The video is 1/8th speed.

We can predict the velocity of the sphere from the other experiments.

In several of the posted experiments the original rotational speed is returned to the cylinder and spheres "combination" at the end of the experiment. This means that the motion has to be maintained throughout the entire length of the experiment.

The ballistic pendulum proves that the small spheres can only give Linear Newtonian Momentum to the larger cylinder and spheres combination. Let's look at the experiments that start with a spinning combination; that then move to the spheres having all the motion; and then back to a spinning combination. These experiments can only conserve Linear Newtonian Momentum; because half of the experiment is the same as a ballistic pendulum experiment. The motion of the small spheres is being transferred to a larger combined mass of the cylinder and spheres.

So the first half (of these motion conserving experiments) has to conserve Linear Newtonian Momentum as well; because that is where the spheres got there motion.  If the spheres can give it back then they must have received it.

This experiment is the first half of the motion returning experiments. And this experiment must conserve Linear Newtonian Momentum. All the Linear Newtonian Momentum of the spinning cylinder must be transferred to the sphere; with the exception of the pendulum movement of the cylinder and air resistance.

The cylinder is suspended from only one side by two strings. This causes the cylinder to rotate, unhindered, counterclockwise.  The string of the sphere is wrapped in the other direction. The sphere stays put until the cylinder rotates down to it. The input motion is the spinning cylinder; or the total distance dropped at the point where the cylinder is stopped.

The cylinder starts throwing the sphere as soon as contact is made. It takes a while to transfer all the motion to the sphere; but eventually the sphere has the cylinder stopped. The sphere even lifts the cylinder and counter rotates it a bit.

The cylinder has a mass of approximately 2700 grams; the sphere has a mass of 66 grams; about 40 to 1. If we attribute a fourth of the motion to the swinging cylinder: then that means the sphere is moving about 30 times faster than the cylinder was rotating.

This is a proportional kinetic energy increase of about ½ * 2.7 kg * 1 m/sec * 1 m/sec = 1.35 J; to   ½ * .066 kg * 30 m/sec *30 m/sec = 29.7 J     about 22 times.

If energy were to be conserved the sphere would be rotating about half as fast as the cylinder; how can you unwrap when you are rotating at .50 the rate of rotation. The sphere would have trouble unwrapping at the speeds required for energy conservation. And the experimenter would not be wearing a helmet for fear of getting thumped.

The experimenter can comfortable catch the spinning cylinder with his left arm; but the sphere could put you in the hospital or the funeral parlor.

Quote from: Delburt Phend on May 21, 2018, 04:57:47 PMIf we attribute a fourth of the motion to the swinging cylinder: then that means the sphere is moving about 30 times faster than the cylinder was rotating.

Like you say "IF". however "if" is not based on any data you collected from your experiment. I agree your experiment does show a complete stop of the cylinder but nowhere have you measured the actual speeds involved in this experiment. I also agree with the fact that the total energy input is equal to the drop of the tube to where it comes to a complete stop but again, nowhere do you mention the exact height of where this happens relative to the starting height. You just assume the final speed of the sphere has conserved all the linear momentum of the cylinder and go on to explaining how much energy gain this gives you.
Please share the actual data of this experiment as it's hard to deduce from this video without having some calibration points. Or redo the experiment from a different point of view (looking directly into the tube) and adding a calibration stick perhaps at the front/rear of the view.