@springfield

QuoteI can't make the numebrs workr for that? I'm just working out for that example were looking for 3,750 joules. The energy stored in a capacitor is (C.V^2)/2 so even if the inturn capacitance is 1 microfarad, which would be extremely large, the voltage would have ot be about 90,000 volts to get that amount of energy!! So I canq't see how anywhere clost to that amount of energy (3,750 joules) could be stored in the inturn capacitance - what am I missing?

Everyone wants to put Teslas words in there perspective, let's try his words and his perspective for a change. Tesla said--

Quoteas the capacity effect is proportionate to the square of this difference, the energy stored in the coil as a whole will now be two hundred and fifty thousand as great.

He did not say 1/2 of CVsquared, he did not say CVsquared divided by 2, he said "the capacity effect is proportionate to the square of this difference"---potential difference. That is E=CVsquared
It's funny nobody gets this whatsoever, here is a hint----- If I apply a 50v alternating current at the resonance of Teslas coil the potential difference between wire A and wire B in patent 512340 is now 100v. I will explain this shortly in the Tesla redux thread, I don't want to get thanes thread off topic.

Quote from: allcanadian on April 17, 2008, 03:57:48 PM

He did not say 1/2 of CVsquared, he did not say CVsquared divided by 2, he said "the capacity effect is proportionate to the square of this difference"---potential difference. That is E=CVsquared

@AC,
Seems to be that's pretty much the same thing - proportionate to CV² -Ã,  the constant of proportinality just depends on what units you're using. But maybe we're talking at cross purposes. Could you pls post a link to the other thread you mentioned? tx!
-Mike

PS (latr) - I just had a look at the Tesla bi-filar winding patent, here http://www.tfcbooks.com/patents/coil.htm. He talks about the capacitance "neutralizing" the inductance. I think what he's actually talking about is a resonant circuit where the LC time constant is tailored to the operating frequency - and further he's buildin in the capacitance by the way he winds to coil, to avoid the cost of adding extrenal capacitance. Intresting stuff.

@springfield

QuoteSeems to be that's pretty much the same thing - proportionate to CV2 -  the constant of proportinality just depends on what units you're using

LOL, thats how I always get in to trouble---assuming things
Here is the link----http://www.overunity.com/index.php/topic,4504.0.html

Quote from: allcanadian on April 17, 2008, 03:57:48 PM
@springfield

QuoteI can't make the numebrs workr for that? I'm just working out for that example were looking for 3,750 joules. The energy stored in a capacitor is (C.V^2)/2 so even if the inturn capacitance is 1 microfarad, which would be extremely large, the voltage would have ot be about 90,000 volts to get that amount of energy!! So I canq't see how anywhere clost to that amount of energy (3,750 joules) could be stored in the inturn capacitance - what am I missing?

Everyone wants to put Teslas words in there perspective, let's try his words and his perspective for a change. Tesla said--

Quoteas the capacity effect is proportionate to the square of this difference, the energy stored in the coil as a whole will now be two hundred and fifty thousand as great.

OK, so Tesla says the bifilar winding make (in his example) 250,000 times more effective internal capacitance. But the capacitance is still very small and I still don't see where there's anywhere to store anything even remotely close on 3,750 joules (which would still need 1 microfrad and 90,000 volt!). And by the way I don't think this is a source of energy - it's just a place to temporarily store energy - so I'm still left wonderign where all those extra joules are goign to come from...?
-Mike

Quote from: OilBarren on April 17, 2008, 07:05:24 AM
[ABOVE THE CRITICAL SPEED THRESHOLD THIS SCENARIO WILL ALSO ACCELERATE.

@Thane

Have you actually tried this with a DC motor and observed an acceleration effect on S/C? What sort of DC motor?  I have not observed it, but then, I used very low impedance commutator switched, shunt wound DC permanent magnet motors for driving and loading comparisons. I'm not surprised that I never observed the acceleration effect with these motors. And conventional theory says I shouldn't have been surprised. I haven't heard or read of anyone else (yet) that has observed this effect in a closed system.

I'm all ears now ! You might be a miracle worker after all ! 

Quote from: OilBarren
THERE SHOULD BE A # 6 WHERE ALL COILS ARE IN PARALLEL WHICH WOULD PROVIDE MAX DECELERATION AND REGENERATION.

Correct. But verify it, if you haven't already. It is the most highly probable outcome, but don't take my word for it. The minor magnetic phase differences between the low and high impedance coils connected in parallel on the same cores may yield unforseen results. I think that is unlikely, but try it and see. ?

P.S. - Just a minor correction to your considerations below

LET?S CONSIDER THE INDIVIDUAL COMPONENTS OF A HIGH CURRENT COIL:
HIGH INDUCTIVE REACTANCE  should read LOW INDUCTIVE REACTANCE
LOW DC RESISTANCE
VERY LOW OR NEGLIGIBLE CAPACITIVE REACTANCE

NOW LET?S CONSIDER THE INDIVIDUAL COMPONENTS OF A HIGH VOLTAGE COIL
HIGH CAPACITIVE REACTANCE
HIGH DC RESISTANCE
VERY LOW OR NEGLIGIBLE INDUCTIVE REACTANCE should read HIGH INDUCTIVE REACTANCE

@All
Inductive reactance (XL) is like resistance (R) except that it only exists in a varying magnetic or electric field or current, such as the varying magnetic field of the magnetic rotor.

Inductive reactance (impedance) increases proportional to increases with frequency and/or inductance. A coil which produces high current is low impedance. It has a low inductive reactance. The length and gauge of the wire determine the resistance, and the number of turns and core mass determine the inductance and inductive reactance. Both coils share the same core material, so the number of turns and gauge determine each coils impedance.

Impedance is always rated for a certain frequency. XL = 2 x pi x F frequency x L inductance that is XL = 2 x pi x F x L
Total impedance Z in a coil is the square root of the sum of the impedance XL squared and the resistance R squared. That is Z = sqrt (XL² + R²)

Cheers all.