SMOT - Close to closing the loop ,second video-BIG improvement

[billmehess]

Yes, it is, but the slope are too steep to slow down the ball significantly/visually. I have done both simulations and practical experiments on this. A ball running on a horizontal track, and approach a SMOT ramp, will stop before the ramp an be pushed slightly backwards again, but close enough the ball will be attracted. However, to get close enough, work must be applied. This is because the ball at a given distance, and farther away are magnetized with the flux that is not between the magnets, but the flux that is going from outside one magnet and into the outside of the other magnet. Therfor the ball will have S and N at the same sides as the magnets in the SMOT. But this magnetism will change polarity when the ball are getting close enough between the magnets.

Make a simulation in FEMM, and it is the quite clear what is happening.

Vidar
[/quote
Almost everythting you said here is incorrect.
The ball approaches the SMOT ramp with speed because it is sloped slightly down from when it enters the receiving ramp from the uchannel connecting the two plates. The " work" that must be applied is gravity.
The ball enters the SMOT easily !!!!!
As far a FEMM goes they are unbelievably worthless. A sim will not anticipate what actually will happen. I have seen 100's of sims on overunity.com they always show a working device.
Garbage in garbage out.
Please look at the SMOT2 001 video that shows the second SMOT with the ball approaching the SMOT from a distance making a full270 degree turn entering the magnets going up hill and falling over the end. Its all on the videos!

[billmehess]

I said the OPPOSITE to that... the ONLY reason why the ball can leave the exit part of the gate is due to gravity. To prove my point, take away the fall and have the ball go up the slope and then make it escape the gate on a level track (no falling at all), impossible. It can NOT escape the magnetic fields that brought it there to begin with.

I am not using a level track, when the ball falls off the track into the scoop it exits the scoop onto a higher level than if the scoop was not used. The receiving platform is angled slightly downwards so that the ball (due to gravity) will roll to the end down the uschannel and onto the receiving plate which is also sloped slightly downward to the SMOT uchannel. The second video with the second quickly made SMOT shows it CLEARLY entering the Smot up an incline and over the end.
Why would I take away the fall at the end??? Its that energy in the fall and the interaction of the scoop which causes the whole thing to work.
The videos are in front of you.
Are you saying that the ball will not enter the SMOT
Are you saying the ball will not move uphill
Are you saying the ball will no exit the SMOT
Are you saying the ball does not roll completely around (270 Degrees.)
Are you saying that even though the drop is 2 " it does not come within 1/2 " of the entry
Are you saying that the second SMOT showing the ball moving from a distance does not enter the SMOT go up hill and exit it.
I still need to solve this last 1/2" Since the video shows all of the above then thats it.
Bill

[Low-Q]

Almost everythting you said here is incorrect.
The ball approaches the SMOT ramp with speed because it is sloped slightly down from when it enters the receiving ramp from the uchannel connecting the two plates. The " work" that must be applied is gravity.
The ball enters the SMOT easily !!!!!
As far a FEMM goes they are unbelievably worthless. A sim will not anticipate what actually will happen. I have seen 100's of sims on overunity.com they always show a working device.
Garbage in garbage out.
Please look at the SMOT2 001 video that shows the second SMOT with the ball approaching the SMOT from a distance making a full270 degree turn entering the magnets going up hill and falling over the end. Its all on the videos!

As I said, I have not only used simulations to see this repelling effect, but also practical experiments. The ball did repel the enterance of the smot (The area a few inches before the SMOTs enterance. Maybe the ball didn't knew better? No. This practical experiment did without doubt show a definite repelling area. I will try to find the video of it which I postet here at OU.com some time ago.

Anyways, if you are right, and my practical experiment isn't valid, why don't you just close the loop, and post a video of a selfrunner? Closing a SMOT isn't that straight forward. If there is excess energy to fight against friction only, the only matter of a working model is to reduce the friction slightly - not even necessary to have 100% frictionless design - it should work quite easily.

Vidar

[Low-Q]

Are you saying that the ball will not enter the SMOT
Are you saying the ball will not move uphill
Are you saying the ball will no exit the SMOT
Are you saying the ball does not roll completely around (270 Degrees.)
Are you saying that even though the drop is 2 " it does not come within 1/2 " of the entry
Are you saying that the second SMOT showing the ball moving from a distance does not enter the SMOT go up hill and exit it.
I still need to solve this last 1/2" Since the video shows all of the above then thats it.
Bill

The ball move uphill with respect to gravity.
The ball moves downwards with respect to the magnetic field.
The ball are assisted with a weak force over some distance to move the ball up the track.

To move a mass up a slight hill do not require much force to do, but you need more distance to it. Over a distance of 5 inches, we can calculate the total energy consumed in this operation. However, when the ball is on the top and wants to drop down, it will require a greater force to prevent the ball from falling vertically. The magnetic field is not strong enough to keep the ball from falling, but strong enough to pull the ball up a slight slope. This is because the force is distributed over a greater distance - a sort of a gear ratio due to the slight uphill.

- You can easily move a 2 ton car up a slight hill, but not be able to hold it back from falling vertically at the end of the hill. This is the principle of operation of a SMOT too.

The ball rolls possibly 270 degrees, but that isnt interesting. The only interesting is to achieve a 360++ degree run.
The 2" drop isn't a fall with acceleration of gravity at 9.82m/s^2. The magnetic field will reduce the acceleration in the fall to less than 9.82m/s^2 because there is a magnetic field which wants to keep the ball from falling, and therfor take away some kinetic energy from the ball in the fall.

The easies way to solve the 1/2" problem is to let the track end 1/2" higher so the ball freely can enter the SMOT again. You claims there is no repelling force to prevent the ball from entering the SMOT, right? So what is the problem? The only problem left is to make a smoother track with less friction. Not neccessarily 100% frictionless.

Vidar

[billmehess]

Enough of this bantering , let us agree to disagree.
Bill