Single circuits generate nuclear reactions

[aleks]

also, aleks: what are you referencing with the quote of my post?

Did I quote you? Recently I've quoted Earl and Feynman only.

[aleks]

An LED changes an electron to a photon, so this electron 'leaves' the primary circuit as well.

No, this does not happen that way. Electrons do not leave circuitry, they only transfer energy to LED which is then converted into space EM wave.

Generally, free (conduction) electrons never leave conductor. But I think in the presence of bias field they may "relax" their bounds a bit, and so that can leave conductor a bit (but this is only an idea - I may be totally wrong about it, just trying to get pieces together in the light of my DC acoustic waves hypothesis). Free electrons are always present in conductors - otherwise it would be a dielectric material. Type of material (and ambient conditions like mag.field and temperature) controls number of free electrons present in a given volume of space within conductor.

[Feynman]

yeah i was thinking out loud, hit reload and check the original post. 

[aleks]

yeah i was thinking out loud, hit reload and check the original post. 

OK I also wanted to add that beta particles go from the carbon rod (it becomes positively charged), but electrostatic wave goes into the carbon rod (it then recovers neutral charge). Anyway electrostatic wave should not carry much energy - it's just a thing we should clearly see on the o-scope.

The thing I don't understand is if we are actually 'net' converting the input electrons to output beta rays, shouldn't we be accumulating a net positive charge somewhere?

Well, capacitors "has it", it accumulates +/- charge. In my understanding capacitor is a "double purpose" device: it can accumulate charge and it can produce internal space EM waves: it kind of "stops" electrons thus releasing their EM energy that then strikes electrons on the opposite side. (sorry if I'm wrong)

[Koen1]

So yes, I agree there are two process's here, one is the flow within the primary circuit (aka power source pulsing into the rod), and the other with waves of beta rays leaving the rod and interacting with the surrounding environment.

The thing I don't understand is if we are actually 'net' converting the input electrons to output beta rays, shouldn't we be accumulating a net positive charge somewhere?

Didn't I mention that in my post on beta collection?
I'm sure I did... But it was quite a large piece of text and I can be a bit vague
sometimes so perhaps it wasn't clear?
Yeah, I looked it up, and that is exactly the question I asked in that post.

So what I'm saying is: a "normal" beta emitter loses beta particles and gains a positive charge, while the collector gains beta particles
and negative charge, and the exchange of the charges between the emitter and the collector through a connected wire causes our output current.
What we have here is a stimulated beta emitter. It only emits beta after receiving a jolt from our "activator circuit". So we have this "activator circuit"
pumping jolts of high voltage through the emitter. Then we should still have a similar process as above, so there should be an emission of
beta particles that charges the emitter positively, and the collector catches the beta and becomes negatively charged.
I repeat: if our stimulated emission is similar to natural beta emission, then we should get a positive charge on the emitter right after the
beta burst.
Right?