12 times more output than input, dual mechanical oscillation system !

[ltseung888]

The force imparted by the moving pendulum is always tangential to the path of motion ( orange arrows)
The purple line represents the path a normal pendulum would travel, the red arch shows the path the milkovic pendulum system operates in.
If we divide the period (T) into 4 parts, and analyze the force during each part,
When the pendulum begins, (1/4T) the force is mostly in the horizontal vector, having little or no effect on the leveraged mass to be lifted.
we see that as the pendulum approaches bottom dead center (2/4T)
the force increases as the tangential vectors into alignment with the gravitational (perpendicular) force.
Then as the pendulum leaves the bottom center (3/4T), the force decreases as the tangential vector heads towards the horizontal in the other direction. And finally as it approaches the other end of its swing (4/4T) the force is almost completely in the horizontal again.

Now, during the middle two 4th's (2/4T and 3/4T),
as the pendulum follows the red path, the vertical distance covered (blue) indicates the height or distance over which this force worked.
Force x Distance  This is the equivalent to the force x distance opposing gravity on the other end of the lever, the work done to the weight.
unless you created a perfectly symmetrical weight and lever system, these are probably different forces over different distances, but the energy value (Joules, or Newton-Meters) is equivalent.

here is a some explanation of the tangential force of the pendulum:
http://www.physicsclassroom.com/class/waves/Lesson-0/Pendulum-Motion

http://farside.ph.utexas.edu/teaching/301/lectures/node140.html

and a period calculator
http://hyperphysics.phy-astr.gsu.edu/hbase/pend.html

and heres my diagram:

Good.

Start thinking circular motion.  You will have to consider Centrifugal Force.

1.  You will look at William Skinner Device in a new light.
2.  You will compare a pendulum with an Unbalanced Wheel.  You will realize that the pendulum is effectively a subset of Unbalanced Wheel.
3.  You will realize the Unbalanced Wheel is a subset of the Unbalanced Cylinder.
4.  Before you accuse the over 50 QMOGEN inventions as hoaxes, think again.
5.  Think of the jumping up and down of the trampoline.  Is it possible that gravitational energy is lead-out by the athletes?
6.  When you jump, make your weight coming down higher (Centrifugal Force is added).  Make your weight going up less (Centrifugal Force is subtracted).  Will you keep jumping higher on perfect renounce?  Would you have lead-out or brought-in gravitational energy? 
7.  You cannot rotate but an Unbalanced Wheel or Cylinder can easily do so. However, you or an athlete can jump at the precise moment effectively increasing the rebounding force.

8.  The Milkovic 2SO works on changing Centrifugal Forces...
9.  No Physics Laws are violated in a lead-out energy device.  (see Skinner and RHEAD video again.)

Lawrence
see reply 2826

[ltseung888]

Where does the CF come from,, it comes from the velocity of the weight traveling around an orbit,, how does the weight get that velocity,, from gravity AND the pivot for the arm causing the weight to gain velocity in the path of the orbit.

When the lever is allowed to move down with the weight the increase in the orbit velocity goes down as well, the force from gravity that WAS increasing that velocity is now being used to accelerate the weight straight down,, well more down than around.

This is  the EXACT reason I suggested that you do the one way clutch or bearing tests.

You will find that the pendulum will not even make it back to the starting angle relative to the arm,, and then it has the second value of drop from the arm moving.

I have done these tests,, many years ago and many many times.

I have played a lot with the Skinner setup.

*** Do you mind sharing the results?  The Skinner setup is a clear case of using gravitational energy via Unbalanced Wheels.

I am currently playing with other setups.

I am not saying that gravity can not be used as the source of force needed to make useable work,, what I am saying is the method and interactions you are talking about I have tried exactly and I was never able to even get them to a net zero condition,, they all stopped by themselves.

The reason that you were not able to get them to a net zero position is as follows:

1.  The Milkovic 2SO can only lead-out a small amount of gravitational energy.  It relies on the swing or oscillation of pendulum.  The number of swings per unit time is governed by the length of the string.  That cannot be changed easily.

2.  Once you use the Chan Wheel, you effectively replace the Pendulum with an Unbalanced Wheel.  The rotational speed of the Unbalanced Wheel can be hundreds or thousand times that of the pendulum.

3.  The Centrifugal Force varies as the square of the angular velocity.  Once you increase the rotational speed, the Centrifugal Force will also increase.  The quantity of lead-out gravitational energy will also increase.

4.  You can easily improve the performance with the use an Unbalanced Cylinder.  That is the Tsinghua University Energy Multiplier QMOGEN.  That is the State Secret of China.

5.  If you do the experiment outside China and that you are NOT a Chinese Citizen, you do not break any laws and will not be "arrested".  You can benefit the World.

6.  When the quantity of lead-out energy is hundred or many thousand times that compared with the Milkovic case, you can easily harness the lead-out energy.  The many attempts to increase the mass and the size of the Milkovic set up are NOT the theoretical best. 

In any new field of science, experience and traditional concepts may not necessarily be an asset...

Lawrence
see reply 2826

[MarkE]

Good.

Start thinking circular motion.  You will have to consider Centrifugal Force.

1.  You will look at William Skinner Device in a new light.
2.  You will compare a pendulum with an Unbalanced Wheel.  You will realize that the pendulum is effectively a subset of Unbalanced Wheel.
3.  You will realize the Unbalanced Wheel is a subset of the Unbalanced Cylinder.
4.  Before you accuse the over 50 QMOGEN inventions as hoaxes, think again.
5.  Think of the jumping up and down of the trampoline.  Is it possible that gravitational energy is lead-out by the athletes?
6.  When you jump, make your weight coming down higher (Centrifugal Force is added).  Make your weight going up less (Centrifugal Force is subtracted).  Will you keep jumping higher on perfect renounce?  Would you have lead-out or brought-in gravitational energy? 
7.  You cannot rotate but an Unbalanced Wheel or Cylinder can easily do so. However, you or an athlete can jump at the precise moment effectively increasing the rebounding force.

8.  The Milkovic 2SO works on changing Centrifugal Forces...
9.  No Physics Laws are violated in a lead-out energy device.  (see Skinner and RHEAD video again.)

Lawrence
see reply 2826

And there is no output energy from these worthless devices you keep promoting.  Zip, zero, nada.

[sm0ky2]

1.  The Milkovic 2SO can only lead-out a small amount of gravitational energy.

There is no lead-out energy in the Milkovic device.
All energies have been accounted for, input energy, work done to counter-weight, and frictional, wind resistance losses.
there is not any unaccounted-for amount of energy to attribute to this "lead-out" quantity your refer to.
Lead-Out energy is not present in this device.

[ltseung888]

There is no lead-out energy in the Milkovic device.
All energies have been accounted for, input energy, work done to counter-weight, and frictional, wind resistance losses.
there is not any unaccounted-for amount of energy to attribute to this "lead-out" quantity your refer to.
Lead-Out energy is not present in this device.

It does not matter whether you disagree.  The lead-out energy is there.  The super-set Chan Wheel leads-out much more.  The Super-super set Tsinghua University Energy Multiplier leads out even more.

Look at the William Skinner device.  Does it lead-out gravitational energy via Unbalanced Wheel rotation?

Lawrence
see reply 2826