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Free energy gravity motor design given to the world: Pinwheel Generator

Started by Russell Lee, August 07, 2010, 03:32:12 PM

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tbird

hi all,

i first must say thanks for the kind words.  you may want to take them back when you hear what i have to say now.

to start, i may have been a bit quick pulling the trigger on my last post.  shortly after posting, i noticed i had made a few mistakes.  i didn't change them because i was wondering who was paying attention and if they would be caught.  WELL DONE !!

p-motion, that was a great tip (not sure where i saw it),  attaching the weights to collapseable cylinders (key, attaching).  we'll use this going forward.  i must say now though, "the devil is in the details", so i will probably be a bit nit pickie.

i will try to stay with the original drawings (http://www.squidoo.com/pinwheelgenerator) for now.  if needed later, we can make adjustments and use p-motion's drawing.

first let's break down a complete vertical arm(s).  considering plates 1 & 3, let's make the overall length 52 inches and 4 inches square.  this will be divided into 7 sections (3 per arm & the hub).  at the bottom going up we have, let's say in the first 2 inches, the "Cylinder stop mechanism".  i believe it has been meant to stop here to transfer the water all along. then would be the container section that looks to be about 18 inches (with water in).  that leaves 4 inches for the weight to occupy.  then would come the 4 inch hub.  after that the upper arm which has the same 24 inch over all length, but is now divided a bit different with the weight and water area.

the water transfer tube (1 inch square) would be attached to the outer end of the collapseable cylinders.  taking away the 2ea, 2 inch stop space and adding the 4 inch hub to the 2ea 22 inch container/weight areas, we come up with a 48 inch pipe.  this equals to 48 cubic inches of head which = 1.7388 lbs.(psi), for water.

to figure the weight of the weights, we must apply this to the total surface of the collapseable cylinders.  since they are 4 x 4, we have 16 sq.in.

now the new part.  since we now have an equal amount pulling down (instead of free floating) in the upper container, we only need half as much weight (if this is unclear, ask and i will explain).  so,.. 16sq.in. x 1.7388 / 2 = 13.847lbs.  this only equals the head, so let's add 1 lb for movement.  new weight size is 14.847lbs.

the last thing is the weight of the water in the container.  expanded we have an area of 4 x 4 x 18 = 288 cu.in.  this times .03606 (lbs per cu.in.)= 10.385lbs.

now let's say the water transfer has been completed and the Push bar operation (plate 7) is in progress.  the upper arm will look like this...from the top down, first 2 inches
at this point Cylinder stop mechanism.  this will be the same on both ends, so should balance.  next would be the expanded water container with 10.385lbs. of water.  this will occupy the next 18 inches.  then in the last 4 inches will be the 14.847lb weight.  this may or may not take all of this space.

lower down, after the 4 inch hub, will be an empty space of about 16-18 inches.  it depends on how much space the collapsed container takes.  then the other 14.847lb weight and the collapsed container.  of course the Cylinder stop mechanism takes up the last 2 inches as mentioned above.

with this info, i'll turn it over to p-motion to figure the leverage (i liked his inch pounds).  at first glance, it looks like it might be balanced.  keep your fingers crossed.

tom

It's better to be thought a fool than to open your mouth and prove it!

tbird

p-motion

QuoteNot sure if I'm speaking for others in here not, but me, don't care to be tested. Not into psycho babble !

i'm with you.  sorry for making it sound like that.  i didn't start out trying to test anyone.  it was just an excuse i used to be lazy.

QuoteYou mean the one Bessler was aware of. Could be why you don't remember. The source is someone else's work I've been working on.

you are the one that gave me the thought.  it was while reading your post that the picture came to my mind. whether said exactly or just lead me to see it that way, you get the credit.

QuoteDon't care to give credit to someone who posts a poor design online and let's others do his work for him.
Smart of him if he can get people to do it for him.

i hope you're not pointing this at me.  i just jumped in because i can do a little math.  i left the hard stuff (for me) for you.  from your other post, it looked like you had a handle on it.

just to be clear, I'M SORRY FOR ANYTHING I MAY HAVE SAID THAT WAS INAPPROPRIATE.

tom

ps..  i'm not German
It's better to be thought a fool than to open your mouth and prove it!

Russell Lee

  There seems to be a problem with understanding how this mechanism works.
  This pinwheel configuration of cylinders does not rotate quickly, it only rotates 90 degrees to the next generation cycle.  The spring arm mechanism seems also to have been unseen.  This arm adds almost the energy equal to the weight of a ball toward rotating the mechanism. 
  Basically you have three full weights against two just to rotate the machine (not produce the electricity).  The electricity is produced as the cylinders are stopped.  Three people on one side of the teeter-totter outweigh the two on the other side= rotation secured.
                                              Russell Lee
Quote from: P-Motion on August 09, 2010, 08:31:12 PM
  Hi Tom,
If you want to think I'm a little paranoid, that's okay.
I have taken a lot of heat for what I've been working on.
It's been close to 3 years.
The Pin Wheel Generator is a poor design. What I
believe Bessler built is much better. And some of what I posted is Bessler simplified.
With Bessler's design, the water does not rotate with the wheel. Instead, the
wheel rotates around it. Basically, it is off setting motions. As a lever drops, the water rises to
the next pump, the wheel roates and another lever drops repeating the sequence.
I have spent the last month or 2 doing some work to
try to come up with the best way of building it.
If anything could generate energy, it would be bessler's design. It is VERY efficient.
And a simple build could demontstrate some of what Bessler knew. This is one reason
why I was refering to his drawings, to help demonstrate that he had the knowledge.
I'm not sure if you've heard of him, but he is supposed to have had a wheel that rotated
at 60 rpm. I believe he did do it. The trick is, it was probably his table top wheel. This means it had a small diameter and would require the circumfrence of the wheel to travel less to complete one rotation.
With a larger wheel, power could be devloped to perform work, such as operating as a winch which he is supposed to have done.


                                                                           Jim

Russell Lee

Hello,
  Consider the weight of the balls to be 2000 lbs, then factor in the contribution of the spring arm mechanism at the bottom.
Quote from: tbird on August 08, 2010, 10:41:50 AM
hi,

let's put some numbers to this machine.

let's say all tubing is square.  let's say each arm is 24 inches long (the area of the water to be moved) and 4 inches square, with a 4 inch square hub.  this gives us a total length of 52 inches.  this is the height you have to raise the liquid (let's use water). let's use a 1 inch square tubing to do the transfer.

so,.. there will be 52 cubic inches of water x .03606 lbs. per cubic inch = 1.875 lbs. in the transfer tube.  since the water container is 4 inches squared, we will have a surface area of 16 sq.in. to push against.

so,.. 16 x 1.875 = 30 lbs. this is how much the ball has to weight to equal the water.  to make it go up, we would need something heavier.  let's say 1 lb would do that and overcome the resistance of the water seal in the container.  i think that is being very generous.  this makes the ball weight 31lbs.

so,.. now we have 24 x 4 x4 =  384cu.in. of water in the container.  so, 384 x .03606 =  13.847 lbs.

if we add the weight of the ball (31lbs.), we get a total of 44.847lbs.

now we have to figure the leverage.  since the container is full of water and the ball (next to the axle), it doesn't gain any leverage.  correct me if i'm wrong.

but,.. the ball alone in the other half, rolled out to the end now, gains a 2 to 1 advantage.  this makes it feel as if it weights 62lbs.

conclusion
i think the ball by itself will stay at the bottom (62lbs > 44.847lbs).

did i miss something?

tom

Low-Q

Quote from: Russell Lee on August 07, 2010, 03:32:12 PM
www.squidoo.com/pinwheelgenerator
There is a reason why the ball can push all that water to the top. It is heavier than the water. So how can the filled water container on the top be able to turn the bottom ball clockwise and upwards? The ball will right after the bottom be slightly lifted mor and more by the water from the top position, because any angle on the spoke will lighten the pressure on the ball against the piston which is pushed down. Generally, there should be equal amounts of water in level position and the two balls should be in the middle of each spoke. I think therefor that this design will not work. You need input of external energy in order to expedite the return of the initially potential energy that was last gained. Only in this way you can make this wheel work. In this situation you have a great delay in the process which makes this wheel not only still, but it will counterforce any attemt of rotation.

Vidar