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Overunity Machines Forum



Chas Campbell free power motor

Started by TheOne, June 04, 2007, 10:25:17 PM

Previous topic - Next topic

0 Members and 65 Guests are viewing this topic.

hartiberlin

Okay, upload has started now.
Could take a while as I only have about 22 Kbytes/sec upload rate right now..
Have a look at

www.overunity.com/campbell

There will be 13 parts as a splitted WinRAR archive.
You need the free packer WinRAR to unpack it to AVI again.
e.g. from www.winrar.de

The splitup into 13 x 10 MB parts is much easier to download than a 130 MByte
single file and it slows down the load on my server.
Each part is 10 Mbytes, only the last is about 8 Mbytes.
Hope this helps.
Regards, Stefan.
Stefan Hartmann, Moderator of the overunity.com forum

Tink

Quote from: rMuD on September 07, 2007, 10:43:46 AM
I see nothing more than a basic Lever in the gravity wheel.. 2 balls at 2x the distance to lift 4 balls..  I mean seriously.. put 4 balls on a lever at 1/2 the distance of 2 balls and see if it lifts the 4 balls..  also there is a loss from the gravity moving the balls from the outer wheel to the inner wheel and other mechanical loss.  hope I'm wrong
I am sorry to say, but rMud is right I think.
I failed to see the logic sorry about that, me bad. :(
Synergy is the key to free energy.

hartiberlin

Quote from: rMuD on September 07, 2007, 03:46:40 PM
my calculations were off..   less than 23% of the time will 2 balls be on the down stroke at 3x sized outer wheel

if anyone wants the orginal visio file, just let me know..   base radius of each circle is 2 times the orginal   to be exact  2" 4" 6" is size  the 39 degrees is a theoretical maximum, no slope was provided for the ramps, where the 4" outer wheel has slopes calculated in, maximum at 0 degree slope is 60 degrees

Hi rMuD,
can you please redraw your wheel with 4:1 distance and upload again
a screenshot ?
Many thanks.
Stefan Hartmann, Moderator of the overunity.com forum

Humbugger

Quote from: hartiberlin on September 07, 2007, 04:23:47 PM
Quote from: rMuD on September 07, 2007, 03:46:40 PM
my calculations were off..   less than 23% of the time will 2 balls be on the down stroke at 3x sized outer wheel

if anyone wants the orginal visio file, just let me know..   base radius of each circle is 2 times the orginal   to be exact  2" 4" 6" is size  the 39 degrees is a theoretical maximum, no slope was provided for the ramps, where the 4" outer wheel has slopes calculated in, maximum at 0 degree slope is 60 degrees

Hi rMuD,
can you please redraw your wheel with 4:1 distance and upload again
a screenshot ?
Many thanks.

Gravity assist goes to zero at 3.8637:1  no point in trying 4:1

"At a ratio of 3.8637 to 1, the linear supply and return ramps reach the theoretical limit of having no possible slope left to deliver balls left and right, since the linear vertical chord distance between positions on.the outer wheel is exactly one unit, same as the inner wheel diameter.  At this ratio, the maximum number of balls on the right side at any given moment becomes one."

hartiberlin

So Humbugger,
are you saying, that it works at 3.8637 to 1
or that the wheel can not work  ?

Well, it seems this wheel is more complicated than I thought from the first glance.
Here is why:

We have 12 slots-spikes on the wheel each being 30 degrees apart.

I just drawed it with a 4:1 distance onto paper.
Then you have the leverage of the left side to:

2 balls 0.5 distance from axis x 1 Kg = 1.0 units
2 balls 0.8 distance from axis x 1 Kg = 1.6 units
1 ball   1.0 distance from axis x 1 Kg = 1.0 units
====================================
sum= 3.6 units

On the right side we have then only for 2 x 15 degrees:

1 ball 3.8 distance from axis x 1 Kg = 3.8 units
1 ball 4.0 distance from axis x 1 Kg = 4.0 units
===================================
sum= 7.8 units

So you see , that we have an leverage advantage of
7.8 / 3.6 units = about  2.16

The problem now is, that we have this only for 30 degrees instead
of 60 degrees at the right side.
Although we have enough snooker balls waiting on the top
to go the 30 degrees ride on the right side.
But after some time more snooker balls wil be down then up.

But as we have the leverage advantage of 2.16 to 1 on the right side
and the wheel has also intertia, we always give it a push with a 2.16 leverage
advantage force for 30 degrees, which is stored inside the intertia of the
wheel, so the wheel thinks all the time ( or at least for 30 degrees intervalls)
that someone is pushing it 2.16 harder at the right side, than at the left side...

So, I don?t know... does it work or doesn?t it work
from the mathematical standpoint ?

I am a bit confused now, but it seems this device
is harder to describe than it seems...

Regards, Stefan.
Stefan Hartmann, Moderator of the overunity.com forum