Chas Campbell free power motor

[sm0ky2]

one idea for consistent functionality would be to put two plates of plexi on the outsides of the tracks so the balls dont fall oof, but also you can then slope the buckets, and make holes in the plexi at your "drop points" such that the balls would roll off the buckets onto the inclined plane with ease.

[shruggedatlas]

Gravity Wheel:

The ratio of the Outer diameter of the Inner wheel (where the ball falls into the upward scoop)
should be at 1:2 to the Inner diameter of the Outer wheel (where the balls descend).
The number of balls is not very important, so long as they are spaced radially-symmetrical, so that the same number of balls fall, as are rising.

Important to note is the Mass of the balls. The cummulative mass of 1/2 the number of Descending balls that import gravitational force on the wheel at any moment in time must be sufficient to move the mass of the wheel with no other balls on it.

This is also the ammount of mass that we may pull our excess energy from. (theoretically).
example: 3 descending balls, with a 2 to 1 leverage and 3 ascending balls.
The 3 descending balls impart 6 units of force onto the wheel, 3 (3.00001) units of force are used to lift the 3 ascending balls, leaving us with 3 units of force. If our whel is designed such that it requires 3 units of force to turn it, then we will have a net energy value of 0 and our friend friction will bring it to a stop.

IF  3 units of force are MORE than is required to move the wheel (less wheel mass? better bearings? no load?)
     Then we will have an excess of force imparted on the wheel. - Think this over and let me know what you think.

as i mentioned earlier, the angle of the horizontal planes determines the RPM (multiple balls in the "waiting" position can counter this effect), and you want the Drop Point on the ascending side to be as high as you can, Top Dead Center would be ideal, but this may cause a problem in the extra momentum consumed in bringing the balls around that much further.  On the same note you want your recieving point on the descending side to be as high as possible. so you have a small range of angles to play with, and moving the horizontal ramps vertically until you find the right position, TIMING is very important, one ball MUST drop into the recieving bucket on the descending side at the SAME TIME as a ball is picked up on the recieving bucket of the ascending side.
ALSO one a ball MUST be dropped off at the drop point on the descending side as the SAME TIME as the ball is being dropped off at the top of the ascending side.  Ideally you would have all 4 balls going onto/off of the ramps at the same time, to reduce wheel instability.

if i can figure out how to post a picture on this thing i can illustrate this, but its basically the design that was posted several times earlier. If the mass of the wheel is considerably less than the mass of 1/2 the number of working balls there will be excess energy - in theory.

I think you went off track somewhere.  You are focusing way too much on the mass of the wheel and not enough on the mass of the balls.  The wheel's mass is not that important.  It will accelerate slower, but it will still move no matter how massive it is, assuming low friction (bearings, etc.).  Your mistake is forgetting that there are twice as many balls on the left as the right.

[sm0ky2]

""Your mistake is forgetting that there are twice as many balls on the left as the right.""


This cannot occur. If there are more balls rising than falling, the system will not perpetuate. they have to rise and fall at the same rate or you will run out of balls on one end or the other. (usually up top)

if you meant twice as many balls worth of force - then yes this is true, however there is a limitation with the wheels mass, and the balls not being able to overcome the forces stopping the wheel. The wheel does not want to spin on its own, and there is a limitation to how small a force can be and actually cause the wheel to move.
this is where the mass of the balls come into play. also the rate at which the wheel moves is effected by the balls mass (and proportional to the mass of the wheel).

[shruggedatlas]

This cannot occur. If there are more balls rising than falling, the system will not perpetuate. they have to rise and fall at the same rate or you will run out of balls on one end or the other. (usually up top)

You are right about the system not perpetuating.  There are more balls on the left than on the right because they rise twice as slowly on the left side, so they have to be denser in order to keep pace with the balls on the right.  Just look at the drawings and you will see what I am talking about.

[sm0ky2]

This cannot occur. If there are more balls rising than falling, the system will not perpetuate. they have to rise and fall at the same rate or you will run out of balls on one end or the other. (usually up top)

You are right about the system not perpetuating.  There are more balls on the left than on the right because they rise twice as slowly on the left side, so they have to be denser in order to keep pace with the balls on the right.  Just look at the drawings and you will see what I am talking about.

IF there are not the same number of balls rising and falling then your horizontal ramps and/or drop points are off.
The outer balls DO move faster, but they also cover a longer distance with is proportional to the ratio between the two wheels. The balls should all be identicle. If you follow the axial-path as the wheel turns you will see that the balls move in unison.