The Lee-Tseung Lead Out Theory

[Kul_ash]

Dear Kul_ash,

The whole analysis is based on the tension (force) in the string having vertical and horizontal component. 

Since the string itself cannot provide energy, the energy comes from Gravity.  Any Lee-Tseung Pull (including horizontal) that maintains tension on the string will Lead Out Gravitational Energy.

The analysis is never based on perfect horizontal force.  Please do not fall into that trap and mislead yourself and others.

The whole analysis is based on the tension (force) in the string having vertical and horizontal component. 

Ok. lol. The upward vertical component is induced in string because of the upward movement of bob which changed from mg to mgh. mgh is acting downwards and to balance that added tension is induced in string. Now you are saying that string can not do work itself. That is correct but your analysis that gravity is doing work is wrong BECAUSE SOMEONE HAS LIFTED PENDULUM BY ADDING ADDITIONAL FORCE TO THE SYSTEM  AND NOT BECAUSE GRAVITY. 
So now do you see the flow of events:

some force lifted bob --------> mg changed to mgh -------------> to balance mgh, tension in string increased in equal and opposite direction.

So some one lifted bob ---------------> tension in string increased

Now as you always say "Physics can not be wrong and kul_ash can never be wrong"!

[Top Gun]

The whole analysis is based on the tension (force) in the string having vertical and horizontal component. 

Ok. lol. The upward vertical component is induced in string because of the upward movement of bob which changed from mg to mgh. mgh is acting downwards and to balance that added tension is induced in string. Now you are saying that string can not do work itself. That is correct but your analysis that gravity is doing work is wrong BECAUSE SOMEONE HAS LIFTED PENDULUM BY ADDING ADDITIONAL FORCE TO THE SYSTEM  AND NOT BECAUSE GRAVITY. 
So now do you see the flow of events:

some force lifted bob --------> mg changed to mgh -------------> to balance mgh, tension in string increased in equal and opposite direction.

So some one lifted bob ---------------> tension in string increased

Now as you always say "Physics can not be wrong and kul_ash can never be wrong"!

Dear Kul_ash,

Please correct your obvious mistake on this post first.

some force lifted bob --------> mg changed to mgh -------------> to balance mgh, tension in string increased in equal and opposite direction.

mg is force.  mgh is energy.  One cannot balance mgh with force!!!

[Kul_ash]

Dear Kul_ash,

Please correct your obvious mistake on this post first.

some force lifted bob --------> mg changed to mgh -------------> to balance mgh, tension in string increased in equal and opposite direction.

mg is force.  mgh is energy.  One cannot balance mgh with force!!!

You can read it like this: External force did the work of lifting bob to height H. So added tension in string is resulting from balancing mg and trying to pull bob horizontally backwards to original position. String has no force left to do any additional work nither it did the work of lifing bob to height h!
Is it clear now?

[Koen1]

I wonder what happened to Noodledick. Does Anyone know?

Well I can guess...

... he moved to China and changed his name into Lawrence Top Gun Forever Young Tseung,
and started flooding the worlds energy forums with complete bullshit?

and who is this Bob you guys are trying to lift all the time?

[Top Gun]

You can read it like this: External force did the work of lifting bob to height H. So added tension in string is resulting from balancing mg and trying to pull bob horizontally backwards to original position. String has no force left to do any additional work neither it did the work of lifting bob to height h!
Is it clear now?

Dear Kul-Ash,

Please think about revising your above paragraph. 

?O level Physics? demands the calculation of work done by the string based on its tension (force) and displacement.  We can divide the work into vertical and horizontal components.  The vertical work is calculated from the vertical component (T1cos(a) or Mg, 60 units) of the Tension times the increase in height dH.  This is positive work done by the string.

The horizontal work is calculated from the horizontal component (T1sin(a) or F, 10 units) times the horizontal displacement ?dX.  This is negative work or energy supplied by the horizontal force F to be stored in the pendulum system.

Please try to revise your above paragraph with the vigorous physics and mathematics.  Please analyze the Three Forces, the resultant Displacement, the Work done and Energy spent or stored.  I am confident the Indian way of doing the analysis will give the same result as the Chinese way if ?O Level Physics? were taught properly in both Countries.

You may even try the more complex case of a non-perfect horizontal force.  (Which I intend to do some time later for the ideal Lee-Tseung Pull.)  You can demonstrate your physics and mathematics skills in reproducing that analysis.  Hint: it is in spreadsheet form already in one of the previous Tseung posts.