99% working wheel!!!

[pequaide]

A 9 kg rim mass wheel can be accelerated to 1.4007 m/sec by placing a 1 kg mass on its edge and allowing the mass to drop one meter. Acceleration is .981 m/sec and the formula used is d = 1/2at? or d = 1/2v?/a. The motion of the wheel has been caused by a force that is equivalent to 9.81 newtons (1kg) acting for 1.4278 seconds.

If all this motion of the wheel is transferred to the overbalanced mass, the 1 kg mass can move against the force of gravity for 1.4278 seconds. In 1.4278 sec the mass will have risen 10 meters, d = .5 * 9.81 * 1.4278 *1.4278. The overbalanced mass was only dropped one meter.

Do the motion transfer from the wheel to the overbalanced mass and disconnect the mass. Throw the overbalanced mass up for the ascending function of the wheel. 

Broli let your wm2d evaluate the cylinder and spheres (the motion transferring device) and see what it comes up with.

[broli]

A 9 kg rim mass wheel can be accelerated to 1.4007 m/sec by placing a 1 kg mass on its edge and allowing the mass to drop one meter. Acceleration is .981 m/sec and the formula used is d = 1/2at? or d = 1/2v?/a. The motion of the wheel has been caused by a force that is equivalent to 9.81 newtons (1kg) acting for 1.4278 seconds.

If all this motion of the wheel is transferred to the overbalanced mass, the 1 kg mass can move against the force of gravity for 1.4278 seconds. In 1.4278 sec the mass will have risen 10 meters, d = .5 * 9.81 * 1.4278 *1.4278. The overbalanced mass was only dropped one meter.

Do the motion transfer from the wheel to the overbalanced mass and disconnect the mass. Throw the overbalanced mass up for the ascending function of the wheel. 

Broli let your wm2d evaluate the cylinder and spheres (the motion transferring device) and see what it comes up with.

I will if I figure out what you mean.

Acceleration is .981 m/sec

Acceleration? I'm a bit confused here.

[pequaide]

Standard acceleration of gravity is 9.81 m/sec but the one kilogram is accelerating 9 other kilograms for (1 kg / 10 kg) * 9.81 = .981 m/sec. It is the same physics as an Atwood?s machine.

[broli]

Please use correct units then next time... m/s^2

[pequaide]

You are correct m/sec?

The final velocity of a pendulum bob is determined by how far the bob had dropped. The final velocity is not determined by the size of the pendulum or the degrees through which the pendulum has swung. You can use d = ? at? or d = ? v?/a, where d is the distance dropped, to determines the final velocity of a pendulum bob. This velocity tells use what force is available to us for what period of time.

A one kilogram pendulum bob that must accelerate nine other kilograms will have an acceleration of .981 m/sec? instead of 9.81.   We now know d (1 meter) and a (.981 m/sec?), from the equation above (d = ? v?/a) we can determine final velocity (1.4007 m/sec) for 10 kilograms.

The overbalanced mass on a balanced wheel is like a pendulum bob that is accelerating more than just itself.