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What goes up must come down - some thoughts

Started by dieter, August 26, 2008, 04:31:00 PM

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pequaide

Dieter; A 5 kg mass moving 1 m/sec has 5 units of momentum and it will rise 5.1 cm. (d = 1/2 at? or d = 1/2v?/a) this is equal to 1 kg at a height of 25.5 cm.

A 1 kg mass moving 5 m/sec has 5 units of momentum and it will rise 127.4 cm. (d = 1/2 at? or d = 1/2v?/a) this is equal to 1 kg at a height of 127.4 cm.

127.4 is greater than 25.5

Build a machine that conserves momentum while giving the motion of a large object to a smaller portion of itself and you have an energy producing device. Such machines can be built for about $25 and are called cylinder and spheres machines.

dieter

QuoteSuch machines can be built for about $25 and are called cylinder and spheres machines.

Have you built one? If so, then please let us see some pictures.

I would however be happy if we discuss the picture that I used to post in this thread after somebody asked for it. Do you ppl understand how it is meant to work at all? I'm a bit afraid most people don't really take the time to study such plans. Besides, the above plan is already kind of obsolete, but it still shows the basic principle of operation. Current concepts are still based on gravity that is triggering a magnet that will push away an other magnet to get imbalance, 90 degrees out of phase.

Anyway ;) seems like I got to build it, at least meanwhile I won't do anything worse .

pequaide

I have built about 20 energy producing devices. Some models are in freefall and others work on top of a frictionless plane. Photographs can be found on the tech.groups.yahoo.com/group/free_energy/ web site under files posted by pequaide, I labeled the 16 latest 8-15-08, 8-19-08, 8-21-08, and 8-25-08.  I had posted pictures here but for some reason it won?t let me post pictures anymore, maybe my computer is to slow. 

broli

Quote from: pequaide on September 01, 2008, 09:05:16 AM
Dieter; A 5 kg mass moving 1 m/sec has 5 units of momentum and it will rise 5.1 cm. (d = 1/2 at? or d = 1/2v?/a) this is equal to 1 kg at a height of 25.5 cm.

A 1 kg mass moving 5 m/sec has 5 units of momentum and it will rise 127.4 cm. (d = 1/2 at? or d = 1/2v?/a) this is equal to 1 kg at a height of 127.4 cm.

127.4 is greater than 25.5

Build a machine that conserves momentum while giving the motion of a large object to a smaller portion of itself and you have an energy producing device. Such machines can be built for about $25 and are called cylinder and spheres machines.


Thanks for this I didn't realize this before! If you indeed can transfer the whole momentum around you can theoretically make as much excess energy as you like. The problem is building such a machine. Since momentum was formulated through collision experiments and wasn't meant for this kind of stuff. I'll check out your work.

dieter

pequaide, although I don't really understand your devices, the pictures are impressive and I appreciate to see somebody is actually doing somthing in the real world, and not only on plans.
Keep it up and make sure not to get smashed by the oil lobby. Although a new energy source may be the only way for mankind to persist in the near future, such an invention is pretty lethal for its inventor.