RESONANCE EFFECTS FOR EVERYONE TO SHARE

[TinselKoala]

Sort of like this?
(The Tesla powerplant in the picture is drawing about 35 VA from the wall. It's shown lighting a CF bulb, sans power supply, to full brilliance with no wires. It will light as many as you can pack into the space near the bulb, for the same current draw from the mains. There is the standard 1/rsquared falloff with distance, but I believe that can be overcome.)

[sparks]

   @Tinsel

        That's a great picture.   Now we need to find a way to store the voltage and get her back to the input so you can pull the plug.  Some folks just need that I guess.

[Grumpy]

Try a coil of zipcord - 8 to 10 feet - with one wire to each end of the bulb to increase the distance.  Leave the other end of the cord open - like a spiral capacitor.

Just thought of it, have not tried it yet.

[duff]

I understood this before UNTIL you showed that different cap values actually
increased or decreased the amount of current draw from the FG.  I just thought
that when you put a different value cap in, and readjust the FG to the new
resonant frequency of the coil, that was it.  Can someone explain why the
dirrent value caps, even though they were all tuned to resonance, gave
different current draw from the FG.

@clone447

With reference to this video: http://www.youtube.com/watch?v=w6cO40f8Qgk

I'll try to give you a basic explanation.

When the 47uF cap was inserted in parallel with the inductor it brought the circuit to peak resonance. The other capacitors that were tried prior to the 47pF did not achieve peak resonance - in other words the circuit was still slightly capacitive (XC > XL).

As you are aware, resonance is achieved when XC = XL so all capacitors tried up to the 47pf cap left the circuit slightly capacitive. When Luc placed the 68pf cap in the circuit, the light closest to the signal generator got slightly brighter so the circuit probably went slightly inductive (XL > XC).


A parallel resonant circuit will look like a very high resistive load. In this circuit the load looked to be around 3.6 giga ohms so the current that the signal generator would see would be:

I = E / R
I  = 10 / 3.6G = 2.78nA

As you can see, 2.78 nano amperes would not be enought to light the light
closest to the signal generator, however the light that is in the parallel
tank circuit is experiencing a highter circulating current.

You have to look at the current in each branch of the circuit.


Below are the calculations for the load impedance. I've ignored the two lights in the circuit.

[sparks]

Resonance is just a means to an end as far as Mr. Tesla was concerned.  Of course we can get a kid swinging alot faster on a swing with proper input of kinetic energy.  But the Gain of the system is in the heigth of the child over the ground.  The resonant circuit is just a means to pump up the voltage until this voltage becomes relavent to the rest of the whole damn electrical distribution of the Universe.  The secondary or coil of high selfinductance will cause a standing wave.
This is a wave that goes just so far and then returns upon itself in phase.  The amplitude of the wave or intensity is increased with each input pulse.  Energy now being stored in the resounding system.  What is not so apparent is that the crests and troughs of the wave are becoming relavent not only to each other but to the rest of the electrical field about the standing wave.  THERE WILL BE A FLOW OF ENERGY INTO THE SYSTEM IN EXCESS OF THAT NEEDED TO MAINTAIN THE STANDING WAVE due to it's relativity to the electrical polarization of the field about the standing wave.  If the node and antinode of the standing wave fall upon large conducting fields we draw on their relative voltage and our system starts to appear as a short circuit for these large capacitor plates.