Hydrocars Small Engine Formula

[TheNOP]

if my preevious post speculation is true then:

1000cc, 4 stroks, 1000rpm

1000rpm/4 = 250 X 1000cc = 250000cc total intake per minute
14% of 250000cc = 14 X 250000 / 100 = 35000cc
35000cc = 35 lpm of hh


and with 4%
4% of 250000cc = 4 X 250000 / 100 = 10000cc
10000cc = 10 lpm of  hh

[Spewing]

@Spewing
25%/75% ratio seem right to have an explosion.

petrol need 1:14.7 ratio witch is 6.80272/100 or 6.8%

here my speculated part:
hho need 2 times the volume of petrol for equivalent energy, in liquid state, same in gas form ?
~14% should be enough.

it can work with less too, starting from 4% +

that alone don't tell how many lpm is require tho.

My calculations come from ones that already have their engines running today. If they produce this amount of gas then i narrow it right down to the milliseconds. In other words if they produce 10 liters per min, then this means they have exactly 1 cc flowing every 6 Milliseconds, 166 cc's every second, and 10 liters every min, it doesn't get any better than that.. Thats just how flow rate works. "its a time issue here."

If they idle their engine at 800 rpms and they're using 7 liters to do it I know exactly how long the engine is sucking in hydroxy in that second, and i know exactly how much is being consumed, as well as how much was not consumed.

Giving their flow rate, and given their production, It is just not possible for their engine to be consuming what is being produced, When you Block a flow rate it will not remain still, i do not know why so many people have problems understanding that, if your applying 130 cc's a second to your engine and your valve is only open 1/4  th or less the time then you will be loosing 1/4th of your production. Its not guess work, its not rocket science, its just good ol facts.

As far as how much ambient air is mixed with the hydroxy, well i never calculated that because it never concerned me, and it probably never will. The important part is i know what is going on inside the engine and i've tried to teach it. I'm done repeating myself, if one wants to understand then its up to them. I laid the math on the table & I pointed everything out. Every calculation is common since to any mechanic. The data is here if you want to browse threw it.

[TheNOP]

hummm..., not as simple as my calculation above.

the equation at 14% might not run at 1k rpm at all.
same for the 4%.

but 4% is the lowest hh input that can run an engine reliably.
lower then that there are risks of blowing mufflers.

[CrazyEwok]

I always enjoy the banter between you guys!!! But i am suprised that there is no mention from Dankie about his wire for sale and offering a free set of steak knives if we order before this thread hits 10 pages... Hmmmm  But thats all good. i have a question for you all about your amount of HHO delivery calculations. It says here derived from people who have their engines running already... Does that mean they have leaned it right out to the point where the engine almost stalls from lack of fuel? i only ask because i know people that have "cleaned" whole fuel lines because the car is acting like it is running to lean to discover that it was a simple matter of tuning the car rather than putting in more fuel...
Just a question.

[Spewing]

if my preevious post speculation is true then:

1000cc, 4 stroks, 1000rpm

1000rpm/4 = 250 X 1000cc = 250000cc total intake per minute
14% of 250000cc = 14 X 250000 / 100 = 35000cc
35000cc = 35 lpm of hh


and with 4%
4% of 250000cc = 4 X 250000 / 100 = 10000cc
10000cc = 10 lpm of  hh

I dont really understand your math. If your engine is 1000 cc's then that means your engine can suck that amount in on the intake stroke.

You said 1000 rpm's. Divide that by 60 seconds. you'll get 16.6666666 revs on your crank per second. Since it is a 4 stroke your intake valve only opens every other rev, so divide 16.6 rev's into 2, your intake valve opens 8.3 times in one second.

So, if it can inhale 1k cc's every intake stroke, then you must multiply 1k * 8.3 valve openings in that one second. You've inhaled 8300 cc's of something per second.

Since you want to know the sum for 1 min, then 8300 60sec times is 498000 per min. Not sure where your going with this.

Another way is to find the volume of a cylinder. If your cylinder is 2.5 inches wide and moves downward 4 inches on the stroke, you do this math to find the volume.

Height 4
Find the Radius. 2.5 / 2 = 1.25

Square the radius, 1.25 * 1.25 = 1.5625

Multiply the height times PI. 4 * 3.14 = 12.56

Multiply your Squared sum by your HeightPI sum. 12.56 * 1.5625 = 19.625

Convert your now calculated area, volume into Milliliters, Multiply your sum by 16.387064

19.625 * 16.387064 = 321.5 cc's.  Now Multiply by 4 cylinders, 321.5 * 4 = 1286 cc's.

The Above was to give you a clear example of what is meant when a engine is labeled with 1L, or 1000 cc's.