Sup Chesta!

just tryin to keep on keepin on. ;]

Workin on figuring out Atom's ville.  ;]

Mags

Hey Woopy

I ran the circuit. Im not sure how you are figuring your output.

Something I had learned from adding more stages was what amount of voltage and capacitance it takes to get finally 10uf at just <1000v.

If we have 10uf 1000v and transfer all the way to another 10uf cap through the BC, we can get nearly 100% transfer.

At 700v we need 20uf to get 10uf at just less than 1000v with BC
At 500v we need 40uf to get  (same as above)
At 350v we need 80uf to get  (same as above)
At 250v we need 160uf to get (same as above)

Its seems odd that if we have 1  10uf 1000v split down to 2 10uf 500v caps, we cant even get close to achieving 10u 1kv objective through the BC. I think is like 835v from 20uf 500v in full transfer..

So at 835, we can see a loss, heat, other.  That is if 20u 500v is half of 10uf 1kv. When we have a conversion of 20uf 700v to 10 1kv, I can at least see that something is coming as a positive, otherwise I would have to consider 20u 700v to be half of 10uf 1kv.  ;]

Im doing some things with the igniter circuit. You had it going in the cap shorting vids. ;]    To make use of it, possibly instead of just shorting the cap, connect the cap to a BC. It intrigues me to get the Large inductor in the ingniter circuit to continue freewheeling. It keeps a steady state of flow at a low rate from source to charge the cap.
This is key. Like Point and forest explained we are working with a 1/4 cycle LC in the BC   I think, lol tired, correct me if Im wrong.

In the igniter, if the large inductor is rolling all the time, then the cap gets charged from the source, but just with less work from the source.   Lol  again , theory. Tesla said it was an eff improvement. The source doesnt have to bang a charge into the cap when needed and depleted. The source doesnt feel the pulses in the circuit beyond the large inductor. Im just trying to mix it up a bit. 

Mags

I keep having thoughts of using a cap that has 1kv in it, or what ever voltage, just 1k per say.  And we never take from that cap, we only add it in series with another cap to raise the total voltage for potential purposes. I dont quite have it clear as to how I should go about it.

There seem to be some varying ideas as the words, dont kill the dipole.

If we added in series, a cap at 1000v, which can give us larger potentials than we have been dealing with, any time we wish. But we must never allow that cap to become bellow 1kv.

At times it makes some sense, and then I think, well, if its in series, it WILL lose voltage.
So we start with a cap thats 1kv as a reciever and never let it die bellow 1kv..   lol  Again, just ideas so far. 


Mags

Mags

Read Reply #591. I have slow computer and watched only first minute of (unconnected!) oscillations. Amplitude is low but coil in simulation has no ferrite core and we can't simulate bifilar,right ? So multiply obtained 4 volt by ferrite permeability and bifilar energy gain.

Quote from: woopy on April 12, 2011, 02:32:16 PM
...
If i understand well, the reactance is applied in sinusoidal or AC input. So the inductor in AC  does not consume energy.  Does it also apply in DC ?
...

Hi Laurent,

The answer to your question above is no.  If you apply DC to a transformer or an inductance, the current will be determined by the coil DC resistance, after the moments of switch-on. At the instant of switch-on the DC voltage to a transformer or inductance, the current is blocked by the L self inductance plus the copper resistance and after about 5 L/R time the current keeps to the V/R value (R is the coil resistance, V is the DC voltage).
A side note to this: a constant DC current applied will bias the core towards the saturation area in most of the cases and it will keep at that area of the B-H curve, depending on its value, on the number of turns and on the core properties.

Another side note to the AC case you wrote "So the inductor in AC does not consume energy." :  It does not consume real or effective energy but it consumes reactive energy (VAR) which is normally small for a transformer for instance when it is unloaded.

Gyula