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Overunity Machines Forum



The two capacitor paradox debate

Started by onepower, September 02, 2020, 01:19:20 PM

Previous topic - Next topic

0 Members and 6 Guests are viewing this topic.

kajunbee

https://youtu.be/4v0YlultV0w

Not sure what this guys credentials are so you might take it with a grain of salt. I can't envision how this would be possible without some amount of inductance. As far as I know and ideal capacitor has zero resistance and inductance.

WhatIsIt

OnePower,

What are you talking about.
There is no conundrum at all.

If you look equation for energy in cap then you see that
with doubling voltage, energy is four times larger.

That means that energy in parallel 4 caps of 5 V are equal
to 1 cap of 10V.

If you have only 2 caps of 5V,
it is only half of energy of 1 cap of 10V.

V8 told you that voltage follow linear scale and energy exponential.

What did you not understand?

WhatIsIt

Real question is

Can cap of 10V perform 4 times of work than cap of 5V,
as energy equation states?
Or is it false?

kajunbee

Lunkster, another paradox is the energy gain when separating a parallel plate capacitor. You have a capacitor whose plates are separated by a certain distance. Let's say it's capacitance is 50 uf and it's charged to 200 volts. The energy stored would be 1 joule. As you start to separate the plates the voltage will increase and capacitance will decrease. At twice the distance the voltage doubles and capacitance halves. You now have 2 joules of stored energy on the capacitor. Where did the extra energy come from? The explanation you will find is that it required work to separate the plates. In doing so you add energy into the system.

https://youtu.be/ImkQdh8jQ5U

Jeg

Quote from: kajunbee on September 05, 2020, 07:59:13 AM
Lunkster, another paradox is the energy gain when separating a parallel plate capacitor. You have a capacitor whose plates are separated by a certain distance. Let's say it's capacitance is 50 uf and it's charged to 200 volts. The energy stored would be 1 joule. As you start to separate the plates the voltage will increase and capacitance will decrease. At twice the distance the voltage doubles and capacitance halves. You now have 2 joules of stored energy on the capacitor. Where did the extra energy come from? The explanation you will find is that it required work to separate the plates. In doing so you add energy into the system.

Nice kajumbee.
What about removing the dielectric which is far lighter than the plate itself...
What about changing the properties of the dielectric material instead of moving anything...
For everything there is a solution. There just need an effort but everything is possible.

Regards